Question

所以我得到了以下代码：

var lowMin      = 01;
var highMin     = 59;

var minuteList  = [];

for (var i = lowMin; i <= highMin; i++) {
    minuteList  .push(i);
}

我想要的是在1到59之间创建一个如下所示的数组： [5,10,15,20,25,30]等等，直到59岁。

Answer 1

IMO，您可以简单地使用Modulus (%)，即i%5。

// Will evaluate to true if the variable is divisible by 5
variable % 5 === 0 

// Will evaluate to true if the variable is divisible by 2
variable % 2 === 0 

//For your example.
if(i%5 == 0)
{
   minuteList.push(i);
}

＆＃13;

var lowMin      = 01;
var highMin     = 59;

var minuteList  = [];

for (var i = lowMin; i <= highMin; i++) {
    if(i%5 == 0)
    {
       minuteList.push(i);
    }
}  
console.log(minuteList);

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

＆＃13;

Answer 2

你可以让你的循环变量取5步，确保它以5的倍数开始：

var lowMin      = 01;
var highMin     = 59;
var minuteList  = [];

for (var i = Math.ceil(lowMin/5)*5; i <= highMin; i+=5) {
  minuteList.push(i);
}

console.log(minuteList);

Answer 3

试试这个：

export class myTranslatorPipe implements PipeTransform {
    transform(value: string): string {
        //get component here ?
    }   
}

在jquery中循环跳过数字

3 个答案: