我正在使用需要这种结构的库
var items = [
new primitives.orgdiagram.ItemConfig({
id: 0,
parent: null,
title: "Scott Aasrud",
description: "Root",
phone: "1 (416) 001-4567",
email: "scott.aasrud@mail.com",
image: "demo/images/photos/a.png",
itemTitleColor: primitives.common.Colors.RoyalBlue
}),
new primitives.orgdiagram.ItemConfig({
id: 1,
parent: 0,
title: "Ted Lucas",
description: "Left",
phone: "1 (416) 002-4567",
email: "ted.lucas@mail.com",
image: "demo/images/photos/b.png",
itemTitleColor: primitives.common.Colors.RoyalBlue
}),
];
options.items = items;
如何将从PHP json检索到的数据推送到数组?
让我困惑的是new primitives.orgdiagram.ItemConfig
从我的PHP中检索的json就是这部分
id: 0,
parent: null,
title: "Scott Aasrud",
description: "Root",
phone: "1 (416) 001-4567",
email: "scott.aasrud@mail.com",
image: "demo/images/photos/a.png",
itemTitleColor: primitives.common.Colors.RoyalBlue
有人可以帮帮我吗?
谢谢你:)
答案 0 :(得分:1)
尝试以下代码。如果JSON有多个对象,请使用for循环将值推送到数组中。
var items = [];
var item1 = new primitives.orgdiagram.ItemConfig({
id: 0,
parent: null,
title: "Scott Aasrud",
description: "Root",
phone: "1 (416) 001-4567",
email: "scott.aasrud@mail.com",
image: "demo/images/photos/a.png",
itemTitleColor: primitives.common.Colors.RoyalBlue
});
items.push(item1);