我正在尝试开发一种服务,无论何时用户打开应用,我的服务都会识别它。我正在使用这些文件:/ proc / [pid] / cgroup,/ proc / [pid] / cmdline,/ proc / [pid] / oom_score,/ proc / [pid] / oom_score_adj来检查它是否是&#39 ; s是在前台运行的用户应用程序。实际上它正在工作但是当我尝试打开任何游戏时,服务一直都不会识别它。 (该服务仅识别具有最低值的文件(oom_score)。
示例:oom_score for" com.google.android.googlequicksearchbox:interactor"是75,但对于" com.king.candycrushsaga"将是> 150,因此代码永远不会检测到它(如下所示)。
服务代码:
scheduler.scheduleAtFixedRate(new Runnable() {
@Override
public void run() {
s=appManager.getAppRunningForeground();
System.out.println(s);
}
},1,2,SECONDS);
让应用运行的功能:
private ReadWriteFile readWriteFile = new ReadWriteFile();
public String getAppRunningForeground(){
int pid;
File[] files = new File("/proc").listFiles();
int lowestOomScore = Integer.MAX_VALUE;
String foregroundProcess = null;
for (File file : files) {
if (!file.isDirectory() || (!file.getName().matches(("\\d+"))))
continue;
pid = Integer.parseInt(file.getName());
try {
String cgroup = readWriteFile.read(String.format("/proc/%d/cgroup", pid));
String[] lines = cgroup.split("\n");
if (lines.length != 2)
continue;
String cpuSubsystem = lines[0];
String cpuaccctSubsystem = lines[1];
if (!cpuaccctSubsystem.endsWith(Integer.toString(pid)) || cpuSubsystem.endsWith("bg_non_interactive"))
continue;
String cmdline = readWriteFile.read(String.format("/proc/%d/cmdline", pid));
if (cmdline.contains("com.android.systemui")||cmdline.contains("com.google.android.googlequicksearchbox:interactor")) {
continue;
}
int uid = Integer.parseInt(cpuaccctSubsystem.split(":")[2].split("/")[1].replace("uid_", ""));
if (uid > 1000 && uid <= 1038)//System process
continue;
File oomScoreAdj = new File(String.format("/proc/%d/oom_score_adj", pid));
if (oomScoreAdj.canRead()) {
int oomAdj = Integer.parseInt(readWriteFile.read(oomScoreAdj.getAbsolutePath()));
if (oomAdj != 0) {
continue;
}
}
int oomscore = Integer.parseInt(readWriteFile.read(String.format("/proc/%d/oom_score", pid)));
if (oomscore < lowestOomScore) {
lowestOomScore = oomscore;
foregroundProcess = cmdline.replaceAll("\\p{Cntrl}", "");
}
} catch (IOException e) {
e.printStackTrace();
}
}
return foregroundProcess;
}
读取文件的类。
public class ReadWriteFile{
File file;
StringBuilder teste3 = new StringBuilder();
FileOutputStream outputStream;
public static String read(String path) throws IOException {
StringBuilder output = new StringBuilder();
BufferedReader reader = new BufferedReader(new FileReader(path));
output.append(reader.readLine());
for (String line = reader.readLine(); line != null; line = reader.readLine())
output.append('\n').append(line);
reader.close();
return output.toString();
}
}
P.S:不推荐使用getRunningTasks,所以请不要提出建议。
答案 0 :(得分:0)
您可以使用在android api 21中添加的UsageStatsManager
类。请参阅this
问题由me提出并回答。
上面的答案将为您提供一个已排序的应用程序ArrayList,所需的前台应用程序将在ArrayList上的第一个索引号为0。
希望这会有所帮助。
答案 1 :(得分:0)
此方法可以帮助您
void checkForegroundAppCompat()
{
ActivityManager activityManager = (ActivityManager) getSystemService(Context.ACTIVITY_SERVICE);
final List<ActivityManager.RunningTaskInfo> taskInfo = activityManager.getRunningTasks(1);
final ComponentName componentName = taskInfo.get(0).topActivity;
if(!getWhiteListedPackages().contains(componentName.getPackageName()) &&
SecurityStatusManager.isAppsBlockingEnabled(this))
{
int pid = android.os.Process.getUidForName(componentName.getPackageName());
// Kill blick APP here
GRLog.w("KILL Blacklist App Package: " + componentName.getPackageName() + " with pid: " + pid);
killApp(componentName.getPackageName(), pid);
}
}