Question

我有一个Mule流，调用两个REST API，产生两个json列表有效负载。我需要从这两个有效负载中获取合并的json列表。

我设法通过带有自定义聚合器策略的分散 - 聚集流来实现这一目标。但是，为此我必须编写的代码看起来相当混乱而且速度很慢。

有没有办法用dataweave实现这个目标？`

输入Json列表1：

[{ "ID": "1", "firstName": "JANE""familyName": "DOE", "Entities": [{ "ID": "515785", "name": "UNKOWN UNITED", "callSign": "UU" }] }, { "ID": "2", "firstName": "JOHN", "familyName": "DOE", "Entities": [{ "Entities_ID": "515785", "name": "UNKOWN UNITED", "callSign": "UU" }] }]

输入Json list 2：

[{ "ID": "1", "firstName": "JANE", "familyName": "DOE", "Entities": [{ "Entities_ID": "8916514", "name": "UNKOWN INCORPORATED", "callSign": "UI" }] }, { "ID": "4", "firstName": "JAKE", "familyName": "DOE", "Entities": [{ "Entities_ID": "8916514", "name": "UNKOWN INCORPORATED", "callSign": "UI" }] }]

所需的输出是没有重复ID的合并列表：

[{ "ID": "1", "firstName": "JANE", "familyName": "DOE", "Entities": [{ "Entities_ID": "515785", "name": "UNKOWN UNITED", "callSign": "UU" }, { "Entities_ID": "8916514", "name": "UNKOWN INCORPORATED", "callSign": "UI" }] }, { "ID": "2", "firstName": "JOHN", "familyName": "DOE", "Entities": [{ "Entities_ID": "515785", "name": "UNKOWN UNITED", "callSign": "UU" }] }, { "ID": "4", "firstName": "JAKE", "familyName": "DOE", "Entities": [{ "Entities_ID": "8916514", "name": "UNKOWN INCORPORATED", "callSign": "UI" }] }]

Answer 1

这适用于dataweave，其中payload是list1，flowVars.list2是list2

Dim ZipFileObj As Variant
Set ZipFileObj = App.Namespace(ZipFile)
For Each item In ZipFileObj.Items
    If LCase(item) Like LCase("*.xml") Then
        'This is where I need a way to read
        'the contents of the file as a string.
        'Then I can use
        'map.ImportXml(contents)
    End If
Next item

希望这有帮助

使用dataweave合并两个json有效负载

1 个答案: