Question

我的数据库中有一个表，其中有两列，一列START_TIME，另一列END_TIME。列的类型为VARCHAR2。

我想选择这两列之间的时差。

要知道这些列包含哪种数据，我已从下面的这些列中选择了数据。

这是SELECT DISTINCT start_time FROM table_name：

的结果

这是SELECT DISTINCT end_time FROM table_name

的结果

可以做些什么？

Answer 1

您的数据看起来就像包含各种格式的小时一样。＆＃34; 14.75＆＃34;建议小数点是十进制小时。

我建议将全部转换为十进制小时。所以，像这样：

select (case when col like '%:%'
             then cast(regexp_substr(col, '[^:]', 1, 1) as decimal(10, 2)) + cast(right(col, 2) as decimal(10, 2)) / 100
             else cast(col as decimal(10, 2))
        end)

然后，您可以通过转换两者并获取差异来获得时差 - 您将获得十进制小时数。

Answer 2

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SQL选择VARCHAR列类型之间的时间差

2 个答案: