Question

如何删除nsarray中的重复项。例如，我的数组包含以下数据。我想与相邻的日期进行比较以避免重复，但它通过错误。

任何人都可以指导我出错的地方

日历第一 -

( 
2010-09-25 17:00:00 GMT,
"AAA",
2010-09-25 17:00:00 GMT,
"AAA",
2010-09-26 17:00:00 GMT,
"BBB",
2010-09-26 17:00:00 GMT,
"BBB",
2010-09-27 17:00:00 GMT,
"CCCC",
2010-09-27 17:00:00 GMT,
"CCC",
2010-09-28 17:00:00 GMT,
"AAA",
2010-09-28 17:00:00 GMT,
"AAA",
2010-09-29 17:00:00 GMT,
"DDDD",
2010-09-29 17:00:00 GMT,
"DDDD",
2010-09-30 17:00:00 GMT,
"BBBB"
)

我的代码

NSArray dates; //dates contain above values
NSMutableArray *temp_date = [[NSMutableArray alloc] init];

for (int i=0; i<[dates count]; i+=2){
    BOOL day;

    if ([dates count]-2 >i) {
        day = [[dates objectAtIndex:i] compare:[dates objectAtIndex:i+2]];
    }   

    if (day) {
        [temp_date addObject:[dates objectAtIndex:i]];
        [temp_date addObject:[dates objectAtIndex:i+1] ];
    }
}

此致 Sathish所在

Answer 1

你可以使用套装。创建后将自动删除重复项。

NSArray *cleanedArray = [[NSSet setWithArray:dates] allObjects];

请记住，集合是无序的。

根据布伦特的评论，这个问题的最新解决方案将允许您按顺序保留元素。

[[NSOrderedSet orderedSetWithArray:dates] array]

Answer 2

最干净的方式

<html> <head> <title>Springy.js image node demo</title> </head> <body> <script src="jquery-1.11.3.js"></script> <script src="springy.js"></script> <script src="springyui.js"></script> <script src="bluebird.min.js"></script>  <script/> $.ajax({ url: 'https://rawgit.com/theresajbecker/CompBio/master/SuperSmallNodes.json', type: 'GET', dataType: 'json' }).done(function(graphP) { for (var i = 0; i < graphP.elements.nodes.length; i++) { var node = graphP.elements.nodes[i].data.id; var Nmass = graphP.elements.nodes[i].data.mass; console.log('mass'); console.log(graphP.elements.nodes[i].data.mass); console.log('node id'); console.log(graphP.elements.nodes[i].data.id); console.log('station_name'); console.log(graphP.elements.nodes[i].data.station_name); } for (i = 0; i < graphP.elements.edges.length; i++) { var Nnode = graphP.elements.edges[i].data.source; console.log('edges source'); console.log(graphP.elements.edges[i].data.source); console.log('edges target'); console.log(graphP.elements.edges[i].data.target); //console.log(node) } var graph = new Springy.Graph(); for ( i = 0; i < graphP.elements.nodes.length; i++) { var NGnode = graph.newNode({ label: 'graphP.elements.nodes[i].data.id'}); } for ( i = 0; i < graphP.elements.edges.length; i++) { var edge = graph.newEdge({source: graphP.elements.edges[i].data.target}, {target: graphP.elements.edges[i].data.target}); } $(document).ready(function(){ var springy = window.springy = jQuery('#springydemo').springy({ graph: graph, nodeSelected: function(node){ console.log('Node selected: ' + JSON.stringify(node.data)); }, repulsion: 500 }); }); }); </script> <div> <canvas id="springydemo" width="800" height="400" style="border: 1px solid black;"></canvas> </div> </body> </html>

Answer 3

要查找相同的对象，最好使用–indexOfObjectIdenticalTo:或 - indexOfObjectIdenticalTo:inRange:

Answer 4

如果您使用过mutableArray，请使用此选项。

NSArray *copy = [mutableArray copy];

NSInteger index = [copy count] - 1;

for (id object in [copy reverseObjectEnumerator]) {

    if ([mutableArray indexOfObject:object inRange:NSMakeRange(0, index)] != NSNotFound) {
        [mutableArray removeObjectAtIndex:index];
    }
    index--;
}
[copy release];

删除nsarray中的重复项

4 个答案: