“缺少右括号”MySQL错误

Question

我正在尝试运行一个查询，它会将舍入平均值显示为两位小数。这是我的代码，我不知道为什么我一直收到错误。

SELECT 
    ROUND(AVG (Scholarship, 2)) AS 'Average Scholarships'
FROM
    student;

Answer 1

您正在将0/255.0传递给Scholarship, 2函数，该函数只需要一个参数。

您打算将AVG和AVG (Scholarship)传递给2，如下所示：

ROUND

Answer 2

SELECT ROUND(AVG (Scholarship), 2) AS 'Average Scholarships' FROM student;