Array
(
[pid] => 877
[encounter] => 15342
[fee] => 300.00
)
Array
(
[pid] => 877
[encounter] => 15342
[fee] => 300.00
)
Array
(
[pid] => 1422
[encounter] => 15332
[fee] => 600.00
)
Array
(
[pid] => 690
[encounter] => 15335
[fee] => 0.00
)
Array
(
[pid] => 690
[encounter] => 15335
[fee] => 276.30
)
Array
(
[pid] => 690
[encounter] => 15335
[fee] => 0.00
)
Array
(
[pid] => 690
[encounter] => 15335
[fee] => 0.00
)
Array
(
[pid] => 690
[encounter] => 15338
[fee] => 400.00
)
代码
$test_cnt = 0;
test_encounter_pid = array();
foreach($provInnrArr as $dataDispArr){
$test_encounter_pid['pid'] = $dataDispArr['pid'];
$test_encounter_pid['encounter'] = $dataDispArr['encounter'];
$test_encounter_pid['fee'] = $dataDispArr['fee'];
if (in_array($dataDispArr["encounter"], $test_encounter_pid)) {
$test_cnt += $dataDispArr['fee'];
}
}
你好朋友,上面是我的数组我正在尝试只有当pid和遭遇不同时,才能汇总所有数组费用关键值 我得到1,876.30总计但实际我的需要是1,576.30 因为300额外添加第二个数组值。我没有得到如何解决它。
答案 0 :(得分:1)
试试这个,
foreach($array as $val){
if($val['pid'] != "0"){
if (!in_array($val['pid'], $temp_array))
{
$temp_array[] = $val['pid'];
$total += $val['fee'];
}
}
echo $total;
<强> DEMO 强>