未捕获的SyntaxError:具有未知原因的意外令牌}

时间:2016-09-21 02:25:55

标签: javascript php html

我有一个Unexpected token },但我不知道为什么。

enter image description here

这是一张桌子上有一些按钮。单击按钮时,它将调用Javascript功能。

这是我的代码:

<tbody>
<?php $i = 0; foreach ($query as $row){?>
<tr>
    <td><?php echo ++$i; ?></td>
    <td><?php echo $row['address'] . ", " . $row['city'] . ", " . $row['state'] . ", " . $row['country']; ?></td>
    <td>
        <button id ="delete" class = "delete" type="button"  value=<?php echo "\"" . $row['id'] . "\""; ?> onClick="deleteAddress(this.value)">delete</button>
    </td>
    <td>
     //Print this <button id = "edit" class = "edit" type="button" value="7"  onClick = "editAddress( this.value, "23", "323", "323", "iij")" >Edit</button>
        <button id = "edit" class = "edit" type="button" value=<?php echo "\"" . $row['id'] . "\""; ?>  onClick = <?php echo "\"editAddress( this.value" . ", \"" . trim($row['address']) . "\", \"" . $row['city'] . "\", \"" . $row['state'] . "\", \"" . $row['country'] . "\")\""; ?> >Edit</button></td>
    </tr>
</tbody>

 function editAddress(id, address, city, state, country)
 {
     document.getElementById("address_field").value = address;
     document.getElementById("city_field").value = city;
     document.getElementById("state_field").value = state;
     document.getElementById("country_field").value = country;
     document.getElementById("add_new").innerHTML = 'Update Address';
     document.getElementById("add_new").value = id;
     document.getElementById("add_new").onclick = function() { 
        var id = document.getElementById("add_new").value;
        var address = document.getElementById("address_field").value; 
        var city = document.getElementById("city_field").value;
        var state = document.getElementById("state_field").value; 
        var country = document.getElementById("country_field").value;  

        jQuery.ajax({
            type: "POST",
            url: "../wp-content/plugins/add_address_list/insert_address.php",
            data: {functionName : "updateAddress", id : id, address : address, city : city, state : state, country : country},
            success: function(msg){
                window.location.reload();
            }
       }); 
    };
  }                 

IDE没有任何语法错误。不知道为什么。 谢谢。

2 个答案:

答案 0 :(得分:1)

出现错误:

onClick = "editAddress( this.value, "23", "323", "323", "iij")"

或者更确切地说:

onClick = <?php echo "\"editAddress( this.value" . ", \"" . trim($row['address']) . "\", \"" . $row['city'] . "\", \"" . $row['state'] . "\", \"" . $row['country'] . "\")'"; ?> >Edit</button>

应该是:

<button id = "edit" class = "edit" type="button" value=<?php echo "\"" . $row['id'] . "\""; ?>  onClick ='<?php echo "editAddress( this.value" . ", \"" . trim($row['address']) . "\", \"" . $row['city'] . "\", \"" . $row['state'] . "\", \"" . $row['country'] . "\")"; ?> >Edit</button></td>

只需用'括起JavaScript,这样就可以使用双引号,所以它看起来像:

onClick = 'editAddress( this.value, "23", "323", "323", "iij")'

答案 1 :(得分:0)

你忘了用&#34;}&#34;关闭你的FOREACH循环;-)

刚刚放

<?php } ?>
关闭TR之后

应该有效。