如何从json对象中获取特定值,该对象包含angularjs中的json数组

时间:2016-09-18 11:51:44

标签: php mysql angularjs

我从mysql数据库中获取以下数据,其中" comment"来自一张桌子和#34;博客"是另一张桌子。现在我想通过ng-repeat显示这些数据。

{
  "comment":[
    {"comment_id":"3","blog_id":"1","total_comment":"2"},
    {"comment_id":"9","blog_id":"8","total_comment":"3"}
  ],
  "blog":[
    {"id":"9","title":"jquery","description":"this is about jquery","date":"2016-08-27","status":"active"},
    {"id":"8","title":"javascript","description":"this is javascript post","date":"0000-00-00","status":"active"},
    {"id":"1","title":"angularjs","description":"this blog is about angularjs.this blog is about angularjs.this blog is about angularjs.this blog is about angularjs.this blog is about angularjs.this blog is about angularjs.","date":"2016-07-12","status":"active"}
  ]
}

1 个答案:

答案 0 :(得分:0)

如果相信“blog_id”是博客表和评论表之间的公共字段。

在mysql“ON blog.id = comment.blog_id”中编写一个Join查询,以便获得所需的数据,并且可以在ng-repeat中显示响应