Question

以下代码用于回应＆＃34; Open＆＃34;或＆＃34;已关闭＆＃34;如果时间是在上午8:15到下午5:30之间。我试图让它具体到一天。如何整合格式字符＆＃39; D＆＃39;例如，星期一上午8:15 - 下午5:30 ...回声＆＃34;打开＆＃34;，星期六上午8:15 - 下午1:00＆＃34;打开＆＃34;。我希望能够控制每天和每个时间的打开/关闭回声。

当前工作代码仅数小时

<?php
date_default_timezone_set('America/New_York');
$hour = (int) date('Hi');
$open = "yah hoo, we are open";
$closed = "by golly, im closed";

if ($hour >= 0815 && $hour <=1735) {
// between 8:15am and 5:35pm
echo "$open";
} else {
echo "$closed";
}
?>

我想要做的例子：

$hour = (int) date('D Hi');
if ($hours >= 0815 && $hour <=1735 && $hour === 'Mon')
{ echo "$open"; }
else { echo "$closed"; }
if ($hours >= 0815 && $hour <=1300 && $hour === 'Sat')
{ echo "$open"; }
else { echo "$closed"; }

根据The One and Only的答案的另一个例子，它看起来接近我正在寻找的东西，但这也不起作用

<?php
$openDaysArray = array('Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat','Sun');

$thisDate = date('D Hi');

$explode = explode(" ", $thisDate);
$day = $explode[0];
$time = $explode[1];

if (in_array($day, $openDaysArray)) 
if ($time < 815 || $time > 1730 && $day === 'Mon');
if ($time < 815 || $time > 1730 && $day === 'Tue');
if ($time < 815 || $time > 1730 && $day === 'Wed');
if ($time < 815 || $time > 1730 && $day === 'Thu');
if ($time < 815 || $time > 1730 && $day === 'Fri');
if ($time < 815 || $time > 1730 && $day === 'Sat');
if ($time < 815 || $time > 1730 && $day === 'Sun');
{echo 'Open';}
else {echo 'Closed';}
?>

Answer 1

使用switch语句：

$thisDate = date('D Hi');

$hoursOfOpArray = array("Mon_Open" => "815", "Mon_Close" => "1730", "Tue_Open" => "815", "Tue_Close" => "1730"); //repeat for all days too fill this array

$explode = explode(" ", $thisDate);
$day = $explode[0];
$time = (int)$explode[1];

switch($day) {
    case "Sun":
        $status = "Closed";
    break;
    case "Mon":
        $status = ($time < $hoursOfOpArray[$day . "_Open"] || $time > $hoursOfOpArray[$day . "_Close"]) ? "Closed" : "Open";
    break;
    //same as Monday case for all other days
}

echo $status;

这也应该有效：

echo ($day === 'Sun' || ($time < $hoursOfOpArray[$day . "_Open"]) || ($time > $hoursOfOpArray[$day . "_Close"])) ? "Closed" : "Open";

Answer 2

我会这样处理它。设置所有打开时间的数组。如果你知道你在周六和周日关闭了，那么就没有必要在那时继续检查时间，所以先杀掉那里的过程。然后只需找出它周中的哪一天，在$hours数组中查找相应的开始和结束时间，创建要比较的实际DateTime对象（而不是整数）。然后返回相应的消息。

function getStatus() {

    $hours = array(
        'Mon' => ['open'=>'08:15', 'close'=>'17:35'],
        'Tue' => ['open'=>'08:15', 'close'=>'17:35'],
        'Wed' => ['open'=>'08:15', 'close'=>'17:35'],
        'Thu' => ['open'=>'08:15', 'close'=>'22:35'],
        'Fri' => ['open'=>'08:15', 'close'=>'17:35']
    );

    $now = new DateTime();
    $day = date("D");

    if ($day == "Sat" || $day == "Sun") {
        return "Sorry we're closed on weekends'.";
    }

    $openingTime = new DateTime();
    $closingTime = new DateTime();

    $oArray = explode(":",$hours[$day]['open']);
    $cArray = explode(":",$hours[$day]['close']);

    $openingTime->setTime($oArray[0],$oArray[1]);
    $closingTime->setTime($cArray[0],$cArray[1]);

    if ($now >= $openingTime && $now < $closingTime) {
        return "Hey We're Open!";
    }

    return "Sorry folks, park's closed. The moose out front should have told ya.";
}

echo getStatus();

Answer 3

这个有用，补充说明尽可能多地解释。

<?php

date_default_timezone_set('America/New_York');

// Runs the function
echo time_str();

function time_str() {

    if(IsHoliday())
    {
        return ClosedHoliday();
    }           

$dow = date('D'); // Your "now" parameter is implied

    // Time in HHMM
    $hm = (int)date("Gi");

    switch(strtolower($dow)){
            case 'mon': //MONDAY adjust hours - can adjust for lunch if needed
                if ($hm >=    0 && $hm <  830) return Closed();
                if ($hm >= 830 && $hm < 1200) return Open();
                if ($hm >= 1200 && $hm < 1300) return Lunch();
                if ($hm >= 1300 && $hm < 1730) return Open();
                if ($hm >= 1730 && $hm < 2359) return Closed();
                break;
            case 'tue': //TUESDAY adjust hours
                if ($hm >= 830 && $hm < 1730) return Open();
                else return Closed();
                break;              
            case 'wed': //WEDNESDAY adjust hours
                if ($hm >= 830 && $hm < 1730) return Open();
                else return Closed();
                break;              
            case 'thu': //THURSDAY adjust hours
                if ($hm >= 830 && $hm < 1730) return Open();
                else return Closed();
                break;              
            case 'fri': //FRIDAY adjust hours
                if ($hm >= 830 && $hm < 1730) return Open();
                else return Closed();
                break;              
            case 'sat': //Saturday adjust hours
                return Closed();
                break;              
            case 'sun': //Saturday adjust hours
                return Closed();
                break;              

    }           
}

// List of holidays
function HolidayList()
{
// Format: 2009/05/11 (year/month/day comma seperated for days)
return array("2016/11/24","2016/12/25");
}

// Function to check if today is a holiday
function IsHoliday()
{
// Retrieves the list of holidays
$holidayList = HolidayList();
// Checks if the date is in the holidaylist  - remove Y/ if Holidays are same day each year  
if(in_array(date("Y/m/d"),$holidayList))
{ 
    return true;
}else
{
    return false;
}   
}

// Returns the data when open
function Open()
{
    return 'Yes we are Open';
}

// Return the data when closed
function Closed()
{
    return 'Sorry We are Closed';
}   

// Returns the data when closed due to holiday
function ClosedHoliday()
{
    return 'Closed for the Holiday';
}

// Returns if closed for lunch
// if not using hours like Monday - remove all this
// and make 'mon' case hours look like 'tue' case hours
function Lunch()
{
    return 'Closed for Lunch';
}

?>

Answer 4

$o = ['Mon' => [815, 1735], /*and all other days*/'Sat' => [815, 1300]];
echo (date('Hi')>=$o[date('D')][0] && date('Hi')<=$o[date('D')][1]) ? "open": "closed";

完成！不要问。

PHP如果特定的工作日周和时间回应

4 个答案: