我们有一个运行Spring Boot 1.3和Postgres数据库的应用程序。自定义UserType是在数据库中为Json类型定义的。遵循并实现UserType以使用ObjectMapper返回Pojo。它工作得非常好。 但是现在使用Spring boot 1.4,我们得到了这个例外。
自定义用户类型的代码段。
@Override
public Object nullSafeGet(ResultSet resultSet, String[] names, SessionImplementor sessionImplementor, Object owner) throws HibernateException, SQLException {
final String result = resultSet.getString(names[0]);
if(result == null) {
return null;
}
try {
ObjectMapper objectMapper = new ObjectMapper();
Object response = objectMapper.readValue(result.getBytes("UTF-8"), returnedClass());
return response;
} catch (Exception e) {
throw new RuntimeException("Failed to process json request:"+e.getMessage(), e);
}
}
我可以看到发现数据库的响应,而objectmapper也会转换它。返回时会抛出此错误。
org.springframework.core.convert.ConverterNotFoundException:找不到能够从类型[java.util.HashMap]转换为[com.company.component.entity.dto.CustomDataDto]类型的转换器
我们在Spring启动时在WebAppConfiguration中配置了MappingJackson2HttpMessageConverter。
CustomDataDto Pojo:
package com.company.component.entity.dto;
import com.fasterxml.jackson.annotation.JsonInclude;
import org.springframework.boot.jackson.JsonComponent;
import java.io.Serializable;
import java.util.List;
@JsonInclude(value = JsonInclude.Include.NON_EMPTY)
public class CustomDataDto implements Serializable {
private static final long serialVersionUID = 4884047700260085799L;
String id;
List<MessagesDto> messages;
List<CommentsDto> comments;
List<MsgCmtMappingDto> msgCmtMapping;
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
public List<MessagesDto> getComments() {
return comments;
}
public void setComments(List<MessagesDto> comments) {
this.comments = comments;
}
public List<CommentsDto> getMessages() {
return messages;
}
public void setMessages(List<CommentsDto> messages) {
this.messages = messages;
}
public List<MsgCmtMappingDto> getMsgCmtMapping() {
return msgCmtMapping;
}
public void setMsgCmtMapping(List<MsgCmtMappingDto> msgCmtMapping) {
this.msgCmtMapping = msgCmtMapping;
}
@Override
public boolean equals(Object o) {
if (this == o) return true;
if (!(o instanceof CustomDataDto)) return false;
CustomDataDto that = (CustomDataDto) o;
if (!id.equals(that.id)) return false;
if (!messages.equals(that.messages)) return false;
if (!comments.equals(that.comments)) return false;
return msgCmtMapping.equals(that.msgCmtMapping);
}
@Override
public int hashCode() {
int result = id.hashCode();
result = 31 * result + messages.hashCode();
result = 31 * result + comments.hashCode();
result = 31 * result + msgCmtMapping.hashCode();
return result;
}
}
答案 0 :(得分:0)
只需检查您的pojo课
您正在尝试将字符串(来自数据库)显示为map(您的pojo类中的字段)