Question

我有这个表，table1：

+----+-------+----------+
| ID | MONTH | QUANTITY |
+----+-------------+----+
| 1  |   1   |     1    |
| 2  |   2   |     2    |
| 3  |   7   |     3    |
| 4  |   4   |     1    |
| 5  |   2   |     3    |
| 6  |  12   |     8    |
| 7  |   1   |     6    |
+----+-------+----------+

My file php is:

 <?php
include 'bd_cnx.php';
$ret =[];
  $sql = "SELECT 
          FROM 
          ";

  $result = $conn->query($sql);
  if ($result->num_rows > 0){

    while($row = $result->fetch_assoc()){
      //floatval() transforma sirul numeric in numar
      $ret[] =[$row['MONTH'], floatval($row['QUANTITY'])];
          }
  }
  else {
      echo "result 0";
      }
?>

如何返回此表单中的值？ [[1,7]，[2,5]，[3,0]，[4,1]，[5,0]，[6,0]，[7,3]，[8,0]，[ 9,0]，[10,0]，[11,0]，[12,8]]

谢谢！

Answer 1

您可以创建数据库结果的临时数组，然后在（固定的）月份（1-12）上进行循环

$tmp = array();
while($row = $result->fetch_assoc()){
    $tmp[$row['MONTH']] = $row['QUANTITY'];
}

$retTmp = array();
for($i=1;$i<=12;$i++){
    $retTmp[] = "[$i," .(isset($tmp[$i]) ? $tmp[$i] : 0) . "]";
}
$ret = '[' . implode(',', $retTmp) . ']';

Answer 2

使用以下代码。

$finalArray = $store = [];
$sql = "SELECT MONTH,SUM(QUANTITY) FROM `stack` GROUP BY MONTH";

$result = $conn->query($sql);
if ($result->num_rows > 0) {

    while ($row = $result->fetch_assoc()) {
        //floatval() transforma sirul numeric in numar
        $store[$row['MONTH']] = $row['QUANTITY'];
    }
    $finalArray = '[';
    for ($i = 1; $i <= 12; $i++) {
        $finalArray .= "[$i," . (isset($store[$i]) ? $store[$i] : 0) . "]";
        if ($i != 12) {
            $finalArray .= ",";
        }
    }

    $finalArray .= ']';
} else {
    echo "result 0";
}

来自数据库的结果值 - mysql

2 个答案: