Question

您好我在接收器类中使用了以下代码

public class AlarmReceiver extends BroadcastReceiver {

    @Override
    public void onReceive(Context context, Intent intent) {
        Log.e("the time is right","yay!");
        Intent i = new Intent(context, AlarmServie.class);
        context.startService(i);
    }
 }

这里是我在服务类

中使用的代码

public class AlarmServie extends Service {
    @Nullable
    @Override
    public IBinder onBind(Intent intent) {
        return null;
    }

    @Override
    public void onStart(Intent intent, int startId) {
        super.onStart(intent, startId);
        Log.e("onStart:","came" );
     /*  NotificationManager notifyman = (NotificationManager) getSystemService(NOTIFICATION_SERVICE);
        Intent main_activity = new Intent(this.getApplicationContext(), MainActivity.class);
        PendingIntent o = PendingIntent.getActivity(this, 0, main_activity, 0);

        /*Notification noti = new Notification.Builder(this)
                .setContentTitle("Reminder to Pill")
                .setContentText("Click for info")
                .setAutoCancel(true)
                .setContentIntent(o)
                .build();*/
        NotificationManager nm = (NotificationManager) this.getApplicationContext().getSystemService(NOTIFICATION_SERVICE);
        Intent in = new Intent(this.getApplicationContext(), MainActivity.class);
        PendingIntent pending = PendingIntent.getactivity(this, 0, in, 0);
        NotificationCompat.Builder mBuilder =new NotificationCompat.Builder(AlarmServie.this);
        mBuilder.setContentTitle("Pill Reminder");
        mBuilder.setContentText("CLick here to View");
        //mBuilder.setSound(sound);

        TaskStackBuilder ts=TaskStackBuilder.create(this);
        ts.addParentStack(MainActivity.class);
        nm.notify(9999,mBuilder.build());

    }}

我创建此代码以获取通知。当我运行应用程序时，接收器类被触发但它没有移动到服务类来调用notification.can任何人都说代码中有什么错误或者说我如何使用广播获取通知接收器和服务在详细的教程中

这里是清单文件，并告诉我在哪里准确地放置代码

<uses-permission android:name="android.permission.VIBRATE"/>
    <uses-permission android:name="android.permission.WAKE_LOCK"/>
    <uses-permission android:name="com.android.alarm.permission.SET_ALARM"/>


    <application
        android:allowBackup="true"
        android:icon="@mipmap/ic_launcher"
        android:label="@string/app_name"
        android:supportsRtl="true"
        android:theme="@style/AppTheme">
        <activity
            android:name=".MainActivity"
            android:label="@string/app_name"
            android:theme="@style/AppTheme.NoActionBar">
            <intent-filter>
                <action android:name="android.intent.action.MAIN" />

                <category android:name="android.intent.category.LAUNCHER" />



            </intent-filter>
        </activity>
        <receiver android:name=".AlarmReceiver"></receiver>
        <activity android:name=".Set"></activity><!-- ATTENTION: This was auto-generated to add Google Play services to your project for
     App Indexing.  See https://g.co/AppIndexing/AndroidStudio for more information. -->
        <meta-data
            android:name="com.google.android.gms.version"
            android:value="@integer/google_play_services_version" />
    </application>

</manifest>

请详细解释code.please中的问题，确切地说明服务标记的放置位置

Answer 1

你也必须declare service在清单中。启动服务的意图被发送到系统，然后系统尝试使用清单文件中传递的信息找到正确的应用程序组件来处理这个特定的意图。

这应该足够了，但我不确定你是否将服务放在默认包中。

<application>
    ....
    <service android:name=".AlarmServie"/>
    ....
</application>

Answer 2

你的清单看起来应该是这样的

<application
    android:allowBackup="true"
    android:icon="@mipmap/ic_launcher"
    android:label="@string/app_name"
    android:supportsRtl="true"
    android:theme="@style/AppTheme">
    <activity
        android:name=".MainActivity"
        android:label="@string/app_name"
        android:theme="@style/AppTheme.NoActionBar">
        <intent-filter>
            <action android:name="android.intent.action.MAIN" />

            <category android:name="android.intent.category.LAUNCHER" />



        </intent-filter>
    </activity>

    //here is your service
     <service android:name=".AlarmServie" android:enabled="true"/>

    <receiver android:name=".AlarmReceiver"></receiver>
    <activity android:name=".Set"></activity><!-- ATTENTION: This was auto-generated to add Google Play services to your project for
 App Indexing.  See https://g.co/AppIndexing/AndroidStudio for more information. -->
    <meta-data
        android:name="com.google.android.gms.version"
        android:value="@integer/google_play_services_version" />
</application>

android广播接收器和服务获取通知

2 个答案: