我无法编程,结果必须是ORDER BY数字和年份。 每年这些数字都会重新出现,首先我们需要在数字一致的情况下显示当前年份。下面是前一年的排列数字等等。
任何想法
谢谢
SELECT k.ID, k.name, k.lastname, k.number, YEAR(k.year),
(k.prices + IFNULL(z.prices, 0) ) as cijena, ( (k.prices + IFNULL(z.prices, 0)) - IFNULL(u.prices, 0) ) as dug, IFNULL(z.prices, 0) as iznos from
( select ID, name, lastname, prices, year, number, from user group by ID) as u
left join (select sum(prices) as prices, ID1 from uplate group by ID1) as u
on u.ID1 = k.ID
left join (select sum(prices) as prices, IDk from zaduzenje group by IDk) as z
on z.IDk = k.ID
GROUP BY k.ID
答案 0 :(得分:0)
问题解决了
SELECT k.ID, k.name, k.lastname, k.number, YEAR(k.year),
(k.prices + IFNULL(z.prices, 0) ) as cijena, ( (k.prices + IFNULL(z.prices, 0)) - IFNULL(u.prices, 0) ) as dug, IFNULL(z.prices, 0) as iznos from
( select ID, name, lastname, prices, year, number, from user group by ID) as k
left join (select sum(prices) as prices, ID1 from uplate group by ID1) as u
on u.ID1 = k.ID
left join (select sum(prices) as prices, IDk from zaduzenje group by IDk) as z
on z.IDk = k.ID
GROUP BY k.ID
ORDER BY YEAR(k.year) DESC, k.number DESC