我的选择查询总是提示错误,即使我已经在它的末尾加了一个FALSE。
function preparedBy($series){
$this->db->select('CONCAT (users.FirstName,' ',users.MiddleName,' ',users.LastName) as name',FALSE);
$this->db->from ( 'users' );
$this->db->join ( 'entry ', 'entry.ClericalAide = users.UserName');
$this->db->where ( 'entry.Series', $series);
$query = $this->db->get();
return $query->row_array();
}
答案 0 :(得分:0)
你的报价都搞砸了。试试这个:
function preparedBy($series){
$this->db->select('CONCAT (users.FirstName, users.MiddleName, users.LastName) as name',FALSE);
$this->db->from ('users');
$this->db->join ('entry','entry.ClericalAide = users.UserName');
$this->db->where ('entry.Series', $series);
$query = $this->db->get();
return $query->row_array();
}
答案 1 :(得分:0)
尝试将您的功能更改为此
function preparedBy($series){
$this->db->select('CONCAT (users.FirstName,'". ."',users.MiddleName,'". ."',users.LastName) as name",FALSE);
$this->db->from ( 'users' );
$this->db->join ( 'entry ', 'entry.ClericalAide = users.UserName');
$this->db->where ( 'entry.Series', $series);
$query = $this->db->get();
return $query->row_array();
}