我的回复如下:
回应:
response:
{"json":
{"response":
{"servicetype":"",
"functiontype":"",
"statuscode":"0",
"statusmessage":"Success",
"data":[{"graphtype":"piechart",
"xlabel":"state",
"ylabel":"count",
"s1":"contact",
"s2":"User",
"data":["Total Contacts: 1 Users: 20",
[{"x":"Karnataka","s1":"1","s2":"15","lat":"12.9716","long":"77.5946"},
{"x":"New Delhi","s1":"0","s2":"5","lat":"28.6139","long":"77.2090"}]]}]}}}
我需要使用ng-repeat动态插入表行名称,表数据名称。
我的桌子看起来像。
State Contact User
Karnatka 1 15
New Delhi 0 5
答案 0 :(得分:2)
尝试这种方式来访问动态标题和数据。
您的json响应看起来非常复杂且难以访问,尝试尽可能多地从服务器端提供更简单的json响应。
var myApp = angular.module('myApp',[]);
myApp.controller('GreetingController', ['$scope', function($scope) {
$scope.greeting = {"json":
{"response":
{"servicetype":"",
"functiontype":"",
"statuscode":"0",
"statusmessage":"Success",
"data":[{"graphtype":"piechart",
"xlabel":"state",
"ylabel":"count",
"s1":"contact",
"s2":"User",
"data":["Total Contacts: 1 Users: 20",
[{"x":"Karnataka","s1":"1","s2":"15","lat":"12.9716","long":"77.5946"},
{"x":"New Delhi","s1":"0","s2":"5","lat":"28.6139","long":"77.2090"}]]}]}}};
$scope.title = $scope.greeting.json.response.data[0];
$scope.data = $scope.greeting.json.response.data[0].data[1];
}]);
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-app="myApp" ng-controller="GreetingController">
<table>
<tr>
<th>{{title.xlabel}}</th>
<th>{{title.s1}}</th>
<th>{{title.s2}}</th>
</tr>
<tr ng-repeat="row in data track by $index">
<td>{{row.x}}</td>
<td>{{row.s1}}</td>
<td>{{row.s2}}</td>
</tr>
</table>
</div>
答案 1 :(得分:1)
将$scope.graphs = response.data;
存储在变量ex:
<div ng-repeat="graph in graphs">
<table>
<tr>
<th>{{graph.xlabel}}</th>
<th>{{graph.s2}}</th>
<th>{{graph.s1}}</th>
</tr>
<tr ng-repeat="state in graph.data[1]">
<td>{{ state.x }}</td>
<td>{{ state.s2 }}</td>
<td>{{ state.s1 }}</td>
</tr>
</table>
</div>
观点:
{
"name": "example",
"properties": {
"key1": "val1",
"key2": "val2"
}
}