我有这个数组，
[
{"Product":"A","time":"00:21:59","date":"2016-09-05"},
{"Product":"B","time":"00:11:59","date":"2016-09-07"},
{"Product":"A","time":"00:11:59","date":"2016-09-08"}
]
我想让它成为，
Type | Mon | Tue | Wed | Thu | Fri | Sat | Sun
--------------------------------------------------
A |0:21:59| | |0:11:59| | |
B | | |0:11:59| | | |
这是此表示的数组，
[{"Type":A,"Mon":"0:21:59","Tue":"","Wed":"","Thu":"0:11:59","Fri":"","Sat":"","Sun":""},
{"Type":B,"Mon":"","Tue":"","Wed":"0:11:59","Thu":"","Fri":"","Sat":"","Sun":""}]
如何使用Underscore制作？ 我试图使用_.object，但我认为这不是解决方案。
答案 0 :(得分：2)
你需要遍历数组。下划线模板使用普通的旧JavaScript，通过<% %>标记嵌入。使用_.each或Array#forEach迭代数组。
答案 1 :(得分：1)
您可以使用/**
* Start SpringBoot server
*/
@SpringBootApplication(scanBasePackages= {"com.your.conf.package"})
//@ComponentScan(basePackages = "com.your.conf.package")
public class Application {
public static void main(String[] args) throws Exception {
System.setProperty("server.port","8132"));
System.setProperty("server.tomcat.max-threads","200");
System.setProperty("server.connection-timeout","60000");
ApplicationContext ctx = SpringApplication.run(Application.class, args);
}
}
循环和可选的forEach()参数为每个产品创建对象，然后使用Date#getDay()
thisArg