Question

我收到错误：

将无效操作数键入二进制和＆amp; （有＆＃39; int *＆＃39;和＆＃39; int＆＃39;）

这是我的计划。问题发生在第34行或fscanf num1

    #include <stdio.h>
    #include <stdlib.h>

    FILE *infile;
       FILE *prnt;
      main()
     {
int num1, num2, nums;
char complex;
float fcost;
char name [11];
infile = fopen ("F:/DATA.txt",  "r");
prnt   = fopen ("F:/income.txt",    "w");
if (infile == 0)
{
    printf ("FILE NOT ON DISK\n");
    system("pause");
    return 0;
}
fprintf (prnt, "%-15s %-23s %6s\n\n", "ABAHLMAN", "Program 1", "PAGE 1");
fprintf (prnt, "\n");

fscanf (infile, " %i %i %i %f %c", &nums &num1 &num2 &fcost &name);

while (!feof (infile))
{
    int area = (nums * 200) + (num1 * 300) + (num2 * 450);
    float cost = fcost + (area * 75.00);
    double income = 12 * ((nums *450) + (num1 * 550) + (num2 *700));
    float payback = cost/ income;

    fprintf (prnt, "%-10s %5f %7c %9.2f\n", name, payback, area, cost);
    fscanf (infile, " %d %d %d %f %c", &nums &num1 &num2 &fcost &name);
}

fclose (infile);
fclose (prnt);
return 0;
}

Answer 1

您没有在fscanf()语句中用逗号分隔参数。他们应该是：

fscanf (infile, " %i %i %i %f %s", &nums, &num1, &num2, &fcost, name);

和

fscanf (infile, " %d %d %d %f %s", &nums, &num1, &num2, &fcost, name);

请注意，name是一个数组，当您将其传递给fscanf()时会转换为指针。因此，需要删除&运算符。如评论中所述，%c的格式应为name。

另请参阅：What is array decaying?

我还建议对main()函数使用标准定义。 main() {..}已过时，应予以避免。相反，您可以将其写为int main(int)。

Answer 2

我看到一些问题。首先，没有逗号分隔scanf的参数。

接下来，fscanf的最后一个参数应为%s格式，并且name不会&传递。

接下来，feof不是控制循环的方法，你应该检查来自fscanf的返回值。

您还在%c中area使用了错误的格式说明符printf，%d

最后请谨慎使用%d或%i格式说明符。除非您希望用户输入除小数之外的其他数字，否则请坚持%d。

所以我建议循环应该是

while (fscanf (infile, " %d %d %d %f %s", &nums, &num1, &num2, &fcost, name) == 5)
{
    int area = nums * 200 + num1 * 300 + num2 * 450;
    float cost = fcost + area * 75.00;
    double income = 12 * (nums * 450 + num1 * 550 + num2 * 700);
    float payback = cost / income;
    fprintf (prnt, "%-10s %5f %7d %9.2f\n", name, payback, area, cost);
}

C无效二进制文件中的错误消息

2 个答案: