我认为您可以使用moment.js

Question

我在使用JS函数时遇到了麻烦。我从这里获得了这个JS代码Difference between two dates in years, months, days in JavaScript

这几个月的工作正常，但是当我试着打电话给那些似乎工作正常的日子时，它会显示30天应该是24天。有人能看到代码有什么问题吗？

    function monthDiff(d1, d2) {
        var months;
        months = (d2.getFullYear() - d1.getFullYear()) * 12;
        months -= d1.getMonth() + 1;
        months += d2.getMonth();
        return months <= 0 ? 0 : months;
    }
    function daysInMonth(date) {
        return new Date(date.getYear(), date.getMonth() + 1, 0).getDate();
    }    
function diffDate(date1, date2) {
    if (date2 && date2.getTime() && !isNaN(date2.getTime())) {
        var months = monthDiff(d1, d2);
        var days = 0;

        if (date1.getUTCDate() >= date2.getUTCDate()) {
            days = date1.getUTCDate() - date2.getUTCDate();
        }
        else {
            months--;
            days = date1.getUTCDate() - date2.getUTCDate() + daysInMonth(date2);
        }

        // Use the variables months and days how you need them.
    }
}

这里是使用函数的var

var     months = monthDiff(new Date(), options.timestamp ) % 12 + 1,
        days = daysInMonth(new Date()),

Answer 1

尝试这个简短，准确的代码：

var _MS_PER_DAY = 1000 * 60 * 60 * 24;

// a and b are javascript Date objects
var a = new Date("7/13/2010");
var b = new Date("12/15/2010");

function dateDiffInDays(a, b) {
  // Discard the time and time-zone information.
  var utc1 = Date.UTC(a.getFullYear(), a.getMonth(), a.getDate());
  var utc2 = Date.UTC(b.getFullYear(), b.getMonth(), b.getDate());

  return Math.round((utc2 - utc1) / _MS_PER_DAY);
}

Answer 2

我认为您可以使用moment.js

不要再重新发明轮子。

只需插入Moment.js Date Range Plugin。

实施例

＆＃13;

var starts = moment('2014-02-03 12:53:12');
var ends   = moment();

var duration = moment.duration(ends.diff(starts));

// with ###moment precise date range plugin###
// it will tell you the difference in human terms

var diff = moment.preciseDiff(starts, ends, true); 
// example: { "years": 2, "months": 7, "days": 0, "hours": 6, "minutes": 29, "seconds": 17, "firstDateWasLater":  false }


// or as string:
var diffHuman = moment.preciseDiff(starts, ends);
// example: 2 years 7 months 6 hours 29 minutes 17 seconds

document.getElementById('output1').innerHTML = JSON.stringify(diff)
document.getElementById('output2').innerHTML = diffHuman

＆＃13;

<html>
<head>

  <script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.14.1/moment.min.js"></script>

  <script src="https://raw.githubusercontent.com/codebox/moment-precise-range/master/moment-precise-range.js"></script>

</head>
<body>
  
  <h2>Difference between "NOW and 2014-02-03 12:53:12"</h2>
  <span id="output1"></span>
  <br />
  <span id="output2"></span>
  
</body>
</html>

＆＃13;

Answer 3

这是一个函数，它将返回以年，月和日数表示的差异：

＆＃13;

function dateDiff(d1, d2) {
    var years = 0, months = 0, days = 0, arr;
    if (d1 > d2) { // call inverse
        interval = dateDiff(d2, d1);
        return {
            years: -interval.years, 
            months: -interval.months, 
            days: -interval.days
        };
    }
    days = d2.getDate() - d1.getDate();
    if (days < 0) {
        months--;
        days+= new Date(new Date(d2).setDate(0)).getDate();
    }
    months += d2.getMonth() - d1.getMonth();
    if (months < 0) {
        years--;
        months+=12;
    }
    years += d2.getFullYear() - d1.getFullYear();
    return {
        years: years, 
        months: months,
        days: days
    };
}

// Sample data
var d1 = new Date('2013-10-20');
var d2 = new Date('2016-12-16')
// Call
var interval = dateDiff(d1, d2);
// Output each number separately
console.log('Years: ', interval.years);
console.log('Months: ', interval.months);
console.log('Days: ', interval.days);

＆＃13;

倒计时还剩几天？

3 个答案:

我认为您可以使用moment.js

实施例