Android工作室

Question

我收到了这段代码。但我得到了错误，因为我认为其中一些被弃用了。我想要发生的只是按钮＆＃34;发送＆＃34;单击它会将用户的位置发送到mysql。

这是android方面。

public void onCreate(Bundle savedInstanceState) {
Button insert=(Button) findViewById(R.id.button1);

insert.setOnClickListener(new View.OnClickListener() {
@Override
    public void onClick(View v) {
        // TODO Auto-generated method stub
        if(gps.canGetLocation()){   
         lat = (float) gps.getLatitude();
         lng = (float) gps.getLatitude();
         lat2= Float.toString(lat);
         lng2= Float.toString(lng);


        insert();
 Toast.makeText(getApplicationContext(), "Success insert - \nLat: " + lat2 +              "\nLong: " + lng2, Toast.LENGTH_LONG).show();   
    }else{
        // can't get location
        // GPS or Network is not enabled
        // Ask user to enable GPS/network in settings
        gps.showSettingsAlert();
    }
    }});
   }

public void insert() {
  ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();

nameValuePairs.add(new BasicNameValuePair("lat2", lat2));
nameValuePairs.add(new BasicNameValuePair("lng2", lng2));

try {
    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost("http://monds.com/example.php");
    httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
    HttpResponse response = httpclient.execute(httppost);
    HttpEntity entity = response.getEntity();
    is = entity.getContent();
    Log.e("pass 1", "connection success ");
} catch (Exception e) {
    Log.e("Fail 1", e.toString());
    Toast.makeText(getApplicationContext(), "Invalid IP Address",
            Toast.LENGTH_LONG).show();
}

try {
    BufferedReader reader = new BufferedReader(new InputStreamReader(
            is, "iso-8859-1"), 8);
    StringBuilder sb = new StringBuilder();
    while ((line = reader.readLine()) != null) {
        sb.append(line + "\n");
    }
    is.close();
    result = sb.toString();
    Log.e("pass 2", "connection success ");
} catch (Exception e) {
    Log.e("Fail 2", e.toString());
}

try {
    JSONObject json_data = new JSONObject(result);
    code = (json_data.getInt("code"));

    if (code == 1) {
        Toast.makeText(getBaseContext(), "Inserted Successfully",
                Toast.LENGTH_SHORT).show();
    } else {
        Toast.makeText(getBaseContext(), "Sorry, Try Again",
                Toast.LENGTH_LONG).show();
    }
} catch (Exception e) {
    Log.e("Fail 3", e.toString());
}
  }

  }

这是我将lat和lng发送到我的数据库的php文件。

$con = mysql_connect($host,$uname,$pwd) or die("connection failed");
mysql_select_db($db,$con) or die("db selection failed");

$lat2=(isset($_REQUEST['lat']) ? $_REQUEST['lat'] : '');
$lng2=(isset($_REQUEST['lng']) ? $_REQUEST['lng'] : '');


 //$lat2=$_REQUEST['lat'];
 //$lng2=$_REQUEST['lng'];

 var_dump($lat2);



 $flag['code']=0;

  if($r=mysql_query("insert into markers_awal values('','$lat2','$lng2')  ",$con))
 {
  $flag['code']=1;
  echo"hi";
}

print(json_encode($flag));
mysql_close($con);
?>