我想比较两个Dictionary<string, string>
实例的内容,而不管它们包含的项目的顺序如何。 SequenceEquals
也会对顺序进行比较,因此我首先按键排序字典,然后调用SequenceEquals
。
是否有一种我可以使用的方法,而不是仅仅比较内容的SequenceEquals
?
如果没有,这是理想的做法吗?
Dictionary<string, string> source = new Dictionary<string, string>();
Dictionary<string, string> target = new Dictionary<string, string>();
source["foo"] = "bar";
source["baz"] = "zed";
source["blah"] = null;
target["baz"] = "zed";
target["blah"] = null;
target["foo"] = "bar";
// sequenceEquals will be false
var sequenceEqual = source.SequenceEqual(target);
// contentsEqual will be true
var contentsEqual = source.OrderBy(x => x.Key).SequenceEqual(target.OrderBy(x => x.Key));
答案 0 :(得分:53)
var contentsEqual = source.DictionaryEqual(target);
// ...
public static bool DictionaryEqual<TKey, TValue>(
this IDictionary<TKey, TValue> first, IDictionary<TKey, TValue> second)
{
return first.DictionaryEqual(second, null);
}
public static bool DictionaryEqual<TKey, TValue>(
this IDictionary<TKey, TValue> first, IDictionary<TKey, TValue> second,
IEqualityComparer<TValue> valueComparer)
{
if (first == second) return true;
if ((first == null) || (second == null)) return false;
if (first.Count != second.Count) return false;
valueComparer = valueComparer ?? EqualityComparer<TValue>.Default;
foreach (var kvp in first)
{
TValue secondValue;
if (!second.TryGetValue(kvp.Key, out secondValue)) return false;
if (!valueComparer.Equals(kvp.Value, secondValue)) return false;
}
return true;
}
答案 1 :(得分:6)
我不知道是否存在现有方法,但您可以使用以下方法(为了简洁省略了args的空检查)
public static bool DictionaryEquals<TKey,TValue>(
this Dictionary<TKey,TValue> left,
Dictionary<TKey,TValue> right ) {
var comp = EqualityComparer<TValue>.Default;
if ( left.Count != right.Count ) {
return false;
}
foreach ( var pair in left ) {
TValue value;
if ( !right.TryGetValue(pair.Key, out value)
|| !comp.Equals(pair.Value, value) ) {
return false;
}
}
return true;
}
最好添加一个重载以允许自定义EqualityComparer<TValue>
。
答案 2 :(得分:0)
如果您使用SortedDictionary,则无需自行应用排序,这可能会更容易使用:
void Main()
{
var d1 = new Dictionary<string, string>
{
["a"] = "Hi there!",
["b"] = "asd",
["c"] = "def"
};
var d2 = new Dictionary<string, string>
{
["b"] = "asd",
["a"] = "Hi there!",
["c"] = "def"
};
var sortedDictionary1 = new SortedDictionary<string, string>(d1);
var sortedDictionary2 = new SortedDictionary<string, string>(d2);
if (sortedDictionary1.SequenceEqual(sortedDictionary2))
{
Console.WriteLine("Match!");
}
else
{
Console.WriteLine("Not match!");
}
}
答案 3 :(得分:-1)
这将检查Values
中是否存在source
的所有target
,忽略了Keys
var result = source.All(x => target.Any(y => x.Value == y.Value));