Angular2:如何将选定的项目从HTML datalist元素传递回组件?

时间:2016-08-31 10:30:14

标签: html angular typescript html-datalist

我有一个简单的组件,其中包括一个用于创建下拉框的内容。这个列表中填充了Web API调用的结果。出于显示目的,我只使用该项目的两个字段。但是,一旦选择了一个元素,我需要对所有其他字段进行处理。如何将整个元素传递回组件?

非常感谢任何帮助。

<h1>Get Locations</h1>
<div>
    <div>
        <input list="browsers" name="browser" #term (keyup)="search(term.value)">
        <datalist id="browsers">
            <option *ngFor="let item of items | async" >
                {{item.code + " " + item.description}}
            </option>
        </datalist>
    </div>
    <input type="submit" value="Click" (click)="onSelect(item)" />
</div>

组件代码如下:

import { Component, OnInit }        from '@angular/core';
import { Observable }       from 'rxjs/Observable';
import { Subject }          from 'rxjs/Subject';
import { LocationService } from './location.service';
import {Location} from './location.component';
import './rxjs-operators';

@Component({
    selector: 'lesson-08',
    templateUrl: './views/lesson08.html',
    providers: [LocationService]
})
export class Lesson08 implements OnInit{

    constructor(private locationService: LocationService) { }

    aLoc: Location;

    ngOnInit() {
        this.aLoc = new Location();
    }

    errorMessage: string;
    locations: Location[];
    mode = 'Observable';
    displayValue: string;

    private searchTermStream = new Subject<string>();

    search(term: string) {
        this.searchTermStream.next(term);
    }

    onSelect(item: Location) {
        // do stuff with this location

    }

    items: Observable<Location[]> = this.searchTermStream
        .debounceTime(300)
        .distinctUntilChanged()
        .switchMap((term: string) => this.locationService.search(term));
    }

1 个答案:

答案 0 :(得分:0)

调用方法的(click)事件应该在选中的选项上。您声明的&#34;项目&#34;只在* ngFor的范围内知道,所以在其子级别上。你宣称它太高了。