我想使用AWK获取以下电子表格,其中名字和姓氏在一列中:
Peter, Griffin, 31 Spooner St, Quahog
Homer, Simpson, 732 Evergreen Terr, Springfield
Fred, Flintstone, 301 Cobblestone Way, Bedrock
并输出到新的电子表格,其中名字和姓氏都有自己的列:
awk '{print $1 "," $2} {FS=","} {print $3} {FS=" "}' spreadsheet.csv
我已尝试动态更改字段分隔符,例如:
import smtplib
from socket import gaierror, timeout
class DataHandler:
is_logged_in = None
is_connected = None
server_conn = None
user_address = ''
user_passwd = ''
@staticmethod
def try_connect():
try:
DataHandler.server_conn = smtplib.SMTP('smtp.gmail.com', 587, timeout=1) # The place where the connection is checked
DataHandler.is_connected = True
except (smtplib.SMTPException, gaierror, timeout):
DataHandler.is_connected = False # Connection status changed upon a connection error
但它似乎没有这样的方式,我得到了一个混乱的混乱。这可能是使用AWK吗?
答案 0 :(得分:2)
只要在第一个基于,
的字段中找到空格,就添加一个逗号:
awk 'BEGIN {FS=OFS=","} {sub(/ /, ", ", $1)}1' file
# ^ ^^
# find a space... ... replace it with , plus space
使用您的文件:
$ awk 'BEGIN {FS=OFS=","} {sub(/ /, ", ", $1)}1' file
Peter, Griffin, 31 Spooner St, Quahog
Homer, Simpson, 732 Evergreen Terr, Springfield
Fred, Flintstone, 301 Cobblestone Way, Bedrock
这使用函数sub()
在第一个字段中执行替换。
答案 1 :(得分:2)
用逗号空格替换第一个空格:
$ sed 's/ /, /' file.csv
Peter, Griffin, 31 Spooner St, Quahog
Homer, Simpson, 732 Evergreen Terr, Springfield
Fred, Flintstone, 301 Cobblestone Way, Bedrock
这里,s/ /, /
是替代命令。它取代了找到的第一个
,
。
要更改文件,请使用-i
选项:
sed -i.bak 's/ /, /' file.csv
答案 2 :(得分:1)
您可以将多个分隔符用作 -
awk -F '[ ,]' '{print $1 ", " $2 ", " $3 $4 " " $5 " " $6 ", " $7 " " $8}' file
输出 -
Peter, Griffin, 31 Spooner St, Quahog
Homer, Simpson, 732 Evergreen Terr, Springfield
Fred, Flintstone, 301 Cobblestone Way, Bedrock
你必须跟踪'列'虽然得到了定义。
答案 3 :(得分:1)
另一种可能性。
awk '{$1=$1","}1' file
Peter, Griffin, 31 Spooner St, Quahog
Homer, Simpson, 732 Evergreen Terr, Springfield
Fred, Flintstone, 301 Cobblestone Way, Bedrock