Question

我有这段代码，我收到了这些错误：

警告：mysqli :: query（）：无法在第299行的C：\ xampp \ htdocs \ pliroforiaka \ grammateiakos_upallilos.php中获取mysqli

注意：尝试在第301行的C：\ xampp \ htdocs \ pliroforiaka \ grammateiakos_upallilos.php中获取非对象的属性

警告：mysqli :: close（）：无法在第317行的C：\ xampp \ htdocs \ pliroforiaka \ grammateiakos_upallilos.php中获取mysqli

<table name="table5" id="table5" width="941" border="1" cellspacing="0" cellpadding="3" align="center">
<form name="form5" class="form5" id="form5" action="stoixeiarantevou.php" method="post"> 
<td>
<?php
$sql = "SELECT username FROM giatros";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
?>
<div id="doc">
<select name="Doctor">
<?php
// output data of each row
while($row = $result->fetch_assoc()) {
?>
    <option value="<?php echo $row['Doctor']; ?>"><?php echo $row['username'];?>        </option>
<?php
}
?>
</select>
</div>
<?php
 }
$conn->close();
   ?>
 Ημερομηνία: <input type="text" id="Hmeromhnia" name="Hmeromhnia" required>   <br>
 Ώρα: <input type="text" id="Wra" name="Wra" required><br>
 <input type="button" value="Δημιουργία" id="btnsubmit" onclick="submitForm3()" required>
 </td>
 </form>
 </table>
 <script>
  function submitForm3() {
   // Get the first form with the name
   // Hopefully there is only one, but there are more, select the correct index
   var frm = document.getElementsByName('form5')[0];
   frm.submit(); // Submit
   frm.reset();  // Reset
   alert("Τα στοιχεία σας ανανεώθηκαν επιτυχώς");
   return false; // Prevent page refresh

     }

   </script>
   </td>
   </tr>

Answer 1

这里的问题是您已提前关闭数据库连接。删除此行

$ conn-> close（）;

警告：mysqli :: query（）：无法获取mysqli。我该如何解决？

1 个答案: