Question

我想从用户提供数据并将其插入MySql数据库,,,这是我的代码,,,我的问题是什么？我的应用程序运行....但在我输入我的数据并单击插入按钮后，没有任何内容插入我的数据库....请帮助我

的init.php

<?php

$db_name="project";
$mysql_user="root";
$server_name="localhost";
$connection=mysqli_connect($server_name,$mysql_user,"",$db_name);

if(!$connection)
{
    echo("Connection not successful");
}
else
echo("Connection Successful");


?>

register.php

<?php
require "init.php";
$u_name=$_POST["name"];
$u_password=$_POST["password"];
$u_contact=$_POST["contact"];
$u_country=$_POST["country"];

$sql_query="insert into users (name,password,contact,country) values('$u_name','$u_password','$u_contact','$u_country');";

if(mysqli_query($connection,$sql_query))
{
  //  echo("data inserted");
}
else
{
  //  echo("error");
}


?>

MainActivity.java

public class MainActivity extends AppCompatActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
}

public void goToRegister(View view)
{
    Intent intent=new Intent(this,Register.class);
    startActivity(intent);

}
}

BackgroundTask.java

public class BackgroundTask extends AsyncTask<String,Void,String> {

Context ctx;
    BackgroundTask(Context ctx)
    {
        this.ctx=ctx;
    }


protected String doInBackground(String... params) {

    String reg_url="http://127.0.0.1/prj/register.php";
    String method=params[0];
    if(method.equals("register"))
    {
        String name=params[1];
        String password=params[2];
        String contact=params[3];
        String country=params[4];
        try {
            URL url=new URL(reg_url);
            HttpURLConnection httpURLConnection=(HttpURLConnection) url.openConnection();
            httpURLConnection.setRequestMethod("POST");
            httpURLConnection.setDoOutput(true);
            OutputStream os=httpURLConnection.getOutputStream();

            BufferedWriter bufferedWriter=new BufferedWriter(new OutputStreamWriter(os,"UTF-8"));

            String data= URLEncoder.encode("name","UTF-8")+"="+URLEncoder.encode(name,"UTF-8")+"&"+
                    URLEncoder.encode("password","UTF-8")+"="+URLEncoder.encode(password,"UTF-8")+"&"+
                    URLEncoder.encode("contact","UTF-8")+"="+URLEncoder.encode(contact,"UTF-8")+"&"+
                    URLEncoder.encode("country","UTF-8")+"="+URLEncoder.encode(country,"UTF-8");
            bufferedWriter.write(data);
            bufferedWriter.flush();
            bufferedWriter.close();
            os.close();
            InputStream IS=httpURLConnection.getInputStream();
            IS.close();
            return "Registration Successful";


        } catch (MalformedURLException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
    return null;
}

@Override
protected void onPreExecute() {
    super.onPreExecute();
}

@Override
protected void onPostExecute(String result) {
    Toast.makeText(ctx,result,Toast.LENGTH_LONG).show();
}

@Override
protected void onProgressUpdate(Void... values) {
    super.onProgressUpdate(values);
}
}

Register.java

public class Register extends AppCompatActivity {
EditText eName,ePassword,eContact,eCountry;
String name,password,contact,country;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_register);

    //Declare Edit Text and Casting

    eName= (EditText) findViewById(R.id.EDName);
    ePassword= (EditText) findViewById(R.id.EDPassword);
    eContact= (EditText) findViewById(R.id.EDContact);
    eCountry= (EditText) findViewById(R.id.EDCountry);

}

public void regUser(View view)
{
    name=eName.getText().toString();
    password=ePassword.getText().toString();
    contact=eContact.getText().toString();
    country=eCountry.getText().toString();
    String method="register";
    BackgroundTask backgroundTask=new BackgroundTask(this);
    backgroundTask.execute(method,name,password,contact,country);
    finish();
}
}

Answer 1

将您的doInBackground方法代码更改为：

protected String doInBackground(String... params) {

    String reg_url="http://127.0.0.1/prj/register.php";
    String method=params[0];
    String text = "";
    if(method.equals("register"))
    {
        String name=params[1];
        String password=params[2];
        String contact=params[3];
        String country=params[4];
        try {
            URL url=new URL(reg_url);
            HttpURLConnection httpURLConnection=(HttpURLConnection) url.openConnection();
            httpURLConnection.setRequestMethod("POST");
            httpURLConnection.setDoOutput(true);
            OutputStream os=httpURLConnection.getOutputStream();            

            String data= URLEncoder.encode("name","UTF-8")+"="+URLEncoder.encode(name,"UTF-8")+"&"+
                    URLEncoder.encode("password","UTF-8")+"="+URLEncoder.encode(password,"UTF-8")+"&"+
                    URLEncoder.encode("contact","UTF-8")+"="+URLEncoder.encode(contact,"UTF-8")+"&"+
                    URLEncoder.encode("country","UTF-8")+"="+URLEncoder.encode(country,"UTF-8");
        BufferedWriter bufferedWriter=new BufferedWriter(new OutputStreamWriter(os,"UTF-8"));
            bufferedWriter.write(data);
            bufferedWriter.flush();
           int statusCode = httpURLConnection.getResponseCode();
        if (statusCode == 200) {

            BufferedReader reader = new BufferedReader(new InputStreamReader(httpURLConnection.getInputStream()));
            StringBuilder sb = new StringBuilder();
            String line;

            while ((line = reader.readLine()) != null)
                sb.append(line).append("\n");

            text = sb.toString();
            bufferedWriter.close();
        }


        } catch (MalformedURLException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
    return text;
}

并在你的register.php中：

<?php
require "init.php";
$u_name=$_POST["name"];
$u_password=$_POST["password"];
$u_contact=$_POST["contact"];
$u_country=$_POST["country"];

$sql_query="insert into users (name,password,contact,country) values('$u_name','$u_password','$u_contact','$u_country');";

if(mysqli_query($connection,$sql_query))
{
   echo("data inserted");
}
else
{
  echo "Error: " . $sql . "<br>" . $conn->error . "<br> Error Code = ".$conn->errno;
}


?>

Answer 2

如果您使用的是仿真器，请使用10.0.2.2而不是127.0.0.1。如果使用实际的Android设备，那么使用PHP所在的服务器/机器的IP。当通过wifi使用实际设备时，服务器/您的机器应该在同一网络上。

使用Android Studio将数据插入mysql

2 个答案: