Question

我在数据库中有2个现有表，但我无权更改它们。在下面显示为模型。

class Prenames(models.Model):
    typ = models.DecimalField(max_digits=1, decimal_places=0, db_column='tprpretyp')
    code = models.DecimalField(max_digits=3, decimal_places=0, db_column='tprprecod')
    name = models.CharField(max_length=20, db_column='tprprenam')

class Profiles(models.Model):
    userid = models.CharField(max_length=6, db_column='rmsuserid')
    prename = models.CharField(max_length=4, db_column='rmsprenam', null=True)
    name = models.CharField(max_length=25, db_column='rmsname')
    surname = models.CharField(max_length=25, db_column='rmssurnam')

如果sql我必须

SELECT * FROM Profiles left join Prenames on tprpretyp = int(rmsprenam/1000) and tprprecod = mod(rmsprenam,1000) WHERE trim(rmsuserid) = ?

我已经尝试过的事情：

from rest_framework import serializers
from .models import *

class PrenameSerializer(serializers.ModelSerializer):
    class Meta:
        model = Prenames
        fields = ('type', 'code', 'name')


class ProfileSerializer(serializers.ModelSerializer):
    prenames = PrenameSerializer(read_only=True)

    class Meta:
        model = Profile
        fields = ('userid', 'name', 'surname', 'prenames')

我得到的东西：

{
  "userid": "560174",
  "name": "******",
  "surname": "******"
}

我期待的事情：

{
  "userid": "560174",
  "name": "******",
  "surname": "******"
  "prenames":[
      {
          "type:":10,
          "code": 01,
          "name": "Mr."
      }
  ]
}

我使用django-rest-framework 3.2.5和django 1.6如何序列化它们？

Answer 1

试试这个：

prenames = PrenameSerializer(source="how_you_get_this_field, many=True, read_only=True)

Answer 2

感谢@Aison给了我灵感。这个解决方案并不是我想要的。但它现在拯救了我的生命。来自SerializerMethodField。我决定将ProfileSerializer修改为

class PatientSerializer(serializers.ModelSerializer):
    prenameth = serializers.SerializerMethodField('getprenameth')
    prenameen = serializers.SerializerMethodField('getprenameen')

    def getprenameth(self, obj):
        return obj.prename.name

    def getprenameen(self, obj):
        return obj.prename.en_pre_name

    class Meta:
        model = Patients
        fields = ('userid', 'name', 'surname', 'prenames', 'prenameth', 'prenameen')

这就是我从中得到的。

{
  "userid": "560174",
  "name": "******",
  "surname": "******",
  "prenameth": "นาย",
  "prenameen": "Mr."
}

现在已足够了。

如何在django-rest-framework中使用自定义关系序列化2个模型？

2 个答案: