Question

我从名为view_id的mysql表中获取最后5 history。使用此view_id我将从family_name和company_name表中获取contact_details，company。

现在我想将family_name显示为升序，但不知何故它没有将family_name显示为升序！

这是我的代码：

$getViewID = mysqli_query($link, "SELECT view_id, hid, is_save FROM history WHERE user_id = '$user_id' AND mark_as = 1 GROUP BY view_id LIMIT 5 ");

if( mysqli_num_rows($getViewID) ) {    

   while( $fetchViewId = mysqli_fetch_array($getViewID) ) {
      $viewid = (int) $fetchViewId['view_id'];
      $hid = (int) $fetchViewId['hid'];
      $is_save = (int) $fetchViewId['is_save'];

      $getDetails = mysqli_query($link, "SELECT cd.cdid, cd.family_name, company.company_name FROM contact_details AS cd LEFT JOIN company ON company.cid = cd.cid WHERE cd.cdid = '$viewid' ORDER BY cd.family_name ASC ");            
      if(mysqli_num_rows($getDetails) > 0 ) {
         while($resDetail = mysqli_fetch_array($getDetails)) {
            $cdid = (int) $resDetail['cdid'];         
            $family_name = stripcslashes($resDetail['family_name']);       
            $family_name = str_replace("&amp;", "&", $family_name);
            $company = stripcslashes($resDetail['company_name']);

            if (strlen($family_name) >= 10) {
               $family_name =  substr($family_name, 0, 8);
            }
            if(strlen($company) >= 15) {
                 $company =  substr($company, 0, 14);
            }
            $url_link = "{$url}index.php?redcdid=$cdid";
            if($is_save == 1) {
               $checked = 'checked = "checked"';
            } else {
               $checked = '';
            }
            echo "<li><a href='$url_link'>&nbsp;&nbsp;$family_name - $company </a> <input $checked type='checkbox' name='save_history' class='data_save' data-saveid='$viewid' data-hid='$hid'></li>";
         }                  
      } // contact end here
   }
   echo "<hr/>";
}

为什么Mysql ORDER BY不能使用GROUP BY关键字？

0 个答案: