我有一个.json文件,如下所示:
[
{
"username": "John",
"currency": 8,
"pulls":
[
{
"character": "person"
},
{
"character": "loved one"
}
]
},
{
"username": "Mike",
"currency": 2,
"pulls":
[
{
"character": "noone"
}
]
},
{
"username": "Clara",
"currency": 5,
"pulls":
[
{
"character": "someone"
}
]
}
]
到目前为止我设法做的是修改“货币”:
bool userExists = false;
string jsonPointsString = File.ReadAllText(userPath);
dynamic jsonObjects = JsonConvert.DeserializeObject(jsonPointsString);
foreach (var jsonObject in jsonObjects)
{
if (jsonObject["username"] == user)
{
jsonObject["currency"] += value;
string output = JsonConvert.SerializeObject(jsonObjects, Formatting.Indented);
File.WriteAllText(userPath, output);
userExists = true;
}
}
除了从头开始添加一个全新的条目:
JsonCollection.User user = new JsonCollection.User();
user.username = username;
user.currency = 10;
using (StreamReader r = new StreamReader(userPath))
{
string json = r.ReadToEnd();
List<JsonCollection.User> users = JsonConvert.DeserializeObject<List<JsonCollection.User>>(json);
users.Add(user);
newJson = JsonConvert.SerializeObject(users, Formatting.Indented);
}
File.WriteAllText(userPath, newJson);
然而,无论我尝试什么,我都无法添加另一个元素来“拉”。我的想法是我用一个用户名和一个拉,两个字符串调用一个函数。根据用户名变量,我必须找到相应的Json Entry,并根据pull变量在“pulls”树中创建一个新条目。这就是我能想到的:
public void AddPullToUser(string user, string newPull)
{
user = "Mike"; //test value
string jsonPointsString = File.ReadAllText(userPath);
dynamic jsonObjects = JsonConvert.DeserializeObject(jsonPointsString);
foreach (var jsonObject in jsonObjects)
{
if (jsonObject["username"] == user)
{
//jsonObject["pulls"] = newPull;
JsonCollection.Character pull = new JsonCollection.Character();
pull.character = newPull;
jsonObject["pulls"] = pull;
string output = JsonConvert.SerializeObject(jsonObjects, Formatting.Indented);
File.WriteAllText(userPath, output);
}
}
}
如果我这样做,系统无法将JsonCollection转换为JArray但不使用JArray我不明白如何找到特定的用户树。 在第二步中,必须进一步扩展以不产生重复的“拉动”,但首先必须这样做。
非常感谢任何帮助。
答案 0 :(得分:1)
像这样 -
var json = "[{'username':'John','currency':8,'pulls':[{'character':'person'},{'character':'loved one'}]},{'username':'Mike','currency':2,'pulls':[{'character':'noone'}]},{'username':'Clara','currency':5,'pulls':[{'character':'someone'}]}]";
var obj = JsonConvert.DeserializeObject<List<RootObject>>(json);
var o = obj.FindIndex(a => a.username == "Mike");
obj[o].pulls.AddRange(new List<Pull>{
new Pull{
character = "Modified"
}
});
Console.WriteLine(JsonConvert.SerializeObject(obj));
哪里
public class Pull
{
public string character { get; set; }
}
public class RootObject
{
public string username { get; set; }
public int currency { get; set; }
public List<Pull> pulls { get; set; }
}
或者,您可能对JSON Merge
感兴趣可能的解决方案如下 -
var json = "[{'username':'John','currency':8,'pulls':[{'character':'person'},{'character':'loved one'}]},{'username':'Mike','currency':2,'pulls':[{'character':'noone'}]},{'username':'Clara','currency':5,'pulls':[{'character':'someone'}]}]";
var obj = JArray.Parse(json);
var idx = obj.IndexOf(obj.FirstOrDefault(a => a["username"].ToString() == "Mike"));
((JArray)obj[idx]["pulls"]).Add(JObject.Parse(@"{
'character': 'new one'
}"));
Console.WriteLine(obj[idx]);
/*output -
{
"username": "Mike",
"currency": 2,
"pulls": [
{
"character": "noone"
},
{
"character": "new one"
}
]
} */
答案 1 :(得分:0)
经过一些研究和你的帮助后,我首先能够将与Json的所有交互改变为相同的代码风格。
新条目已更改为:
public void CreateUser(string username)
{
try
{
string jsonUserString = File.ReadAllText(userPath);
var users = JsonConvert.DeserializeObject<List<JsonCollection.User>>(jsonUserString);
users.AddRange(new List<JsonCollection.User> { new JsonCollection.User { username = username, currency = 10, pulls = new List<JsonCollection.Character> { new JsonCollection.Character { character = "TemmieHYPE" } } } });
string output = JsonConvert.SerializeObject(users, Formatting.Indented);
File.WriteAllText(userPath, output);
}
catch
{
Console.WriteLine("Error on CreateUser");
}
}
更新已更改为:
public void UpdateUserStats(string username, decimal value, int selection)
{
try
{
string jsonUserString = File.ReadAllText(userPath);
var users = JsonConvert.DeserializeObject<List<JsonCollection.User>>(jsonUserString);
int user = users.FindIndex(a => (a.username == username));
if (user != -1)
{
switch (selection)
{
case 1:
users[user].currency += value;
break;
case 2:
users[user].secondsOnline += value;
break;
default:
break;
}
string output = JsonConvert.SerializeObject(users, Formatting.Indented);
File.WriteAllText(userPath, output);
//AddPullToUser(username, DateTime.Now.ToString()); //remove on live
}
else
{
CreateUser(username);
}
}
catch
{
Console.WriteLine("Error on UpdateCurrency");
}
}
最重要的是,添加拉动命令将嵌套元素添加到Json现在可以使用以下代码:
public void AddPullToUser(string username, string pulledCharacter)
{
string jsonUserString = File.ReadAllText(userPath);
var users = JsonConvert.DeserializeObject<List<JsonCollection.User>>(jsonUserString);
int alreadyPulled = users.FindIndex(a => (a.username == username) && (a.pulls.FindIndex(b => b.character == pulledCharacter) > 0));
if (alreadyPulled == -1)
{
int user = users.FindIndex(a => (a.username == username));
users[user].pulls.AddRange(new List<JsonCollection.Character> { new JsonCollection.Character { character = pulledCharacter } });
string output = JsonConvert.SerializeObject(users, Formatting.Indented);
File.WriteAllText(userPath, output);
}
}
添加&#34; if(alreadyPulled == -1)&#34;重复的拉动也不会被添加到Json文件中。