如何逐日从两列中获得总延迟？

Question

我在MySql数据库中有一个名为internet的表，其中有3列：id，dropped_at和dropped_to，如图所示

  

如何按日期查找总延迟组？

嗯，我已经尝试过，但它没有正常工作 这是我的MySql代码：

SELECT
    dropped_at,
    dropped_to,
    TIMEDIFF(dropped_to,dropped_at) AS delay
FROM
    internet
WHERE
    WEEKDAY(dropped_at) BETWEEN 0 AND 6 AND 
  WEEK (dropped_at) = WEEK (NOW())
GROUP BY CAST(dropped_to AS DATE)

Answer 1

如果您想要每天的总延迟，那么以下查询将起作用：

SELECT 
 DATE(dropped_at) AS date,
 SUM(TIMESTAMPDIFF(MINUTE,dropped_at,dropped_to)) AS delayInMinutes
FROM internet
GROUP BY date 
ORDER BY date;

注意：延迟时间为MINUTES。您可以根据需要将其更改为任何单位

如果您希望延迟采用 hh:mm:ss 格式，请尝试以下查询

SELECT 
 DATE(dropped_at) AS date,
 SEC_TO_TIME(SUM(TIMESTAMPDIFF(SECOND,dropped_at,dropped_to))) AS delay
FROM internet
GROUP BY date 
ORDER BY date;