Question

我正在尝试根据银行审批状态获取捐款总额，并按礼品类别分组。但是，脚本在单独的行上输出RR和NR捐赠（参见下面的脚本）。似乎案例陈述根本不起作用。

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Answer 1

我相信你正在寻找这个逻辑：

select gift_kind,
       sum(case when c.bank_approval_status = 'AP' then c.charge_amount 
           end) as approved,  
       sum(case when c.bank_approval_status in ('RR', 'NR') then c.charge_amount
           end) as rejected,
       sum(case when c.bank_approval_status in ('AR') then c.charge_amount*-1
           end) as refunded,
       sum(case when c.bank_approval_status not in ('AR','AP','RR','NR') then c.charge_amount
           end) other_status
from charge_log c join
     transactions t
     on c.account_id = t.account_id and
        c.gift_date = t.gift_date and
        c.gift_seq = t.gift_seq and
        C.PLEDGE_NUMBER = t.pledge_number
where c.process_id = 'CHG - 02532' and t.sts = 'A'
group by t.fund_type, t.gift_kind
order by gift_kind asc

注意：

学习使用正确的JOIN语法。从不在FROM子句中使用逗号。
JOIN条件应全部在ON子句中，而不是WHERE子句。
CASE是SUM()的参数。
从bank_approval_status。

GROUP BY

我不知道为什么fund_type位于GROUP BY。你可能有理由这样我离开了。

Answer 2

您需要将case子句放在总和中，然后添加else 0以确保您不会得到null：

sum(case
    when c.bank_approval_status = 'AP' then 
        c.charge_amount else 0 end) approved,  
sum(case    
    when c.bank_approval_status in ('RR','NR') then 
        c.charge_amount else 0 end) rejected,
sum(case    
    when c.bank_approval_status = 'AR' then 
        -c.charge_amount else 0 end) refunded,
sum(case 
    when c.bank_approval_status not in ('AR','AP','RR','NR')  then 
        c.charge_amount else 0 end) other_status

您的group by应该很少出现在汇总中使用的列上（bank_approval_status中的sum）。改为：

group by  gift_kind

根据您的方案，可能需要将其他字段添加到group by子句中，但是将它们放在select和order by子句中也是有意义的。

案例陈述对产出没有影响

2 个答案: