Question

//define index of column
    $columns = array( 
        0 =>'id',
        1 =>'employee_name', 
        2 => 'employee_salary',
        3 => 'employee_age'
        4 =>'employee_City', 
        5 => 'employee_State',
        6 => 'employee_Pin'
    );

    $where = $sqlTot = $sqlRec = "";
    if( !empty($params['search']['value']) ) {   
        $where .=" WHERE ";
        $where .=" ( employee_name LIKE '".$params['search']['value']."%' ";    
        $where .=" OR employee_salary LIKE '".$params['search']['value']."%' ";

        $where .=" OR employee_age LIKE '".$params['search']['value']."%' )";
    }
    // getting total number records without any search
    $sql = "SELECT * FROM `employee` ";
    $sqlTot .= $sql;
    $sqlRec .= $sql;
    //concatenate search sql if value exist
    if(isset($where) && $where != '') {

        $sqlTot .= $where;
        $sqlRec .= $where;
    }

请帮助我，我有3个表，所有表都有一个主键作为table_id如何使用服务器端数据表从3个表中获取数据如何在此代码中实现连接查询。 employee_City，employee_State和employee_Pin存储在第二个表中。使用个人详细信息存储在第三个表中。如何加入所有表格？

Answer 1

我刚刚拿了表城，州，密码的虚拟名称..

尝试使用此查询：

$sql = "SELECT id, employee_name, employee_salary, employee_age, employee_City, employee_State, employee_Pin FROM employee LEFT JOIN city ON employee.cityID = city.id  LEFT JOIN state ON employee.stateID = state.id  LEFT JOIN pincode ON employee.pincodeid = pincode.id  ";

  if( !empty($params['search']['value']) ) {   
        $sql .=" WHERE ";
        $sql .=" ( employee_name LIKE '%".$params['search']['value']."%' ";    
        $sql .=" OR employee_salary LIKE '%".$params['search']['value']."%' ";
        $sql .=" OR employee_age LIKE '%".$params['search']['value']."%' )";
    }
$sql.=" ORDER BY employee_name";

Answer 2

这些链接可以帮助您进行联接查询：

https://www.sitepoint.com/understanding-sql-joins-mysql-database/

http://www.techonthenet.com/mysql/joins.php

使用php在服务器端数据表中内连接

2 个答案: