不太确定'Active Record'是否是正确的术语。 DB? Postgres的?
我正在关注Rails Tutorial并遇到一个非常令人沮丧的问题。我在SO上发现了很多关于人们苦苦挣扎的帖子,但是大多数人都没有找到答案的基础,所以我试图找出我的例子有什么问题。
我的用户控制器
类UsersController< ApplicationController的 before_action:set_user,only:[:show,:edit,:update,:destroy]
# GET /users
# GET /users.json
def index
@users = User.all
end
# GET /users/1
# GET /users/1.json
def show
end
# GET /users/new
def new
@user = User.new
end
# GET /users/1/edit
def edit
end
# POST /users
# POST /users.json
def create
@user = User.new(user_params)
respond_to do |format|
if @user.save
format.html { redirect_to @user, notice: 'User was successfully created.' }
format.json { render :show, status: :created, location: @user }
else
format.html { render :new }
format.json { render json: @user.errors, status: :unprocessable_entity }
end
end
end
# PATCH/PUT /users/1
# PATCH/PUT /users/1.json
def update
respond_to do |format|
if @user.update(user_params)
format.html { redirect_to @user, notice: 'User was successfully updated.' }
format.json { render :show, status: :ok, location: @user }
else
format.html { render :edit }
format.json { render json: @user.errors, status: :unprocessable_entity }
end
end
end
# DELETE /users/1
# DELETE /users/1.json
def destroy
@user.destroy
respond_to do |format|
format.html { redirect_to users_url, notice: 'User was successfully destroyed.' }
format.json { head :no_content }
end
end
private
# Use callbacks to share common setup or constraints between actions.
def set_user
@user = User.find(params[:id])
end
# Never trust parameters from the scary internet, only allow the white list through.
def user_params
params.require(:user).permit(:name, :email)
end
end
我的用户模型
class User < ApplicationRecord
has_many :micropost
validates :name, presence: true
validates :email, presence: true
end
My Microposts Model
class Micropost < ApplicationRecord
belongs_to :user
validates :content, length: { maximum: 140 },
presence: true
end
My Microposts Controller
class MicropostsController < ApplicationController
before_action :set_micropost, only: [:show, :edit, :update, :destroy]
# GET /microposts
# GET /microposts.json
def index
@microposts = Micropost.all
end
# GET /microposts/1
# GET /microposts/1.json
def show
end
# GET /microposts/new
def new
@micropost = Micropost.new
end
# GET /microposts/1/edit
def edit
end
# POST /microposts
# POST /microposts.json
def create
@micropost = Micropost.new(micropost_params)
respond_to do |format|
if @micropost.save
format.html { redirect_to @micropost, notice: 'Micropost was successfully created.' }
format.json { render :show, status: :created, location: @micropost }
else
format.html { render :new }
format.json { render json: @micropost.errors, status: :unprocessable_entity }
end
end
end
# PATCH/PUT /microposts/1
# PATCH/PUT /microposts/1.json
def update
respond_to do |format|
if @micropost.update(micropost_params)
format.html { redirect_to @micropost, notice: 'Micropost was successfully updated.' }
format.json { render :show, status: :ok, location: @micropost }
else
format.html { render :edit }
format.json { render json: @micropost.errors, status: :unprocessable_entity }
end
end
end
# DELETE /microposts/1
# DELETE /microposts/1.json
def destroy
@micropost.destroy
respond_to do |format|
format.html { redirect_to microposts_url, notice: 'Micropost was successfully destroyed.' }
format.json { head :no_content }
end
end
private
# Use callbacks to share common setup or constraints between actions.
def set_micropost
@micropost = Micropost.find(params[:id])
end
# Never trust parameters from the scary internet, only allow the white list through.
def micropost_params
params.require(:micropost).permit(:content, :user_id)
end
end
我的show.html.erb
<p id="notice"><%= notice %></p>
<p>
<strong>Name:</strong>
<%= @user.name %>
</p>
<p>
<strong>Email:</strong>
<%= @user.email %>
<% if @user.micropost.any? %>
<%= @user.micropost.first %>
<% end %>
</p>
<%= link_to 'Edit', edit_user_path(@user) %> |
<%= link_to 'Back', users_path %>
当我加载一个用户页面(在我的情况下是6或7)时,我看到以这种格式输出'某事',但它正在显示 我觉得这是一个Active Record(?)索引?我不知道如何让它显示用户的第一个(或任何)Micropost。
在某些解决方案中,我看到人们使用了render @ user.micropost但是我遇到了一个关于partials的问题(我很熟悉),但教程说你应该能够使用之前使用的语法(aka @ user.email) )解决它。所以我觉得我过于复杂了?
答案 0 :(得分:0)
我的问题是我需要使用
<p id="notice"><%= notice %></p>
<p>
<strong>Name:</strong>
<%= @user.name %>
</p>
<p>
<strong>Email:</strong>
<%= @user.email %>
<% if @user.micropost.any? %>
<%= @user.micropost.first.content %>
<% end %>
</p>
<%= link_to 'Edit', edit_user_path(@user)
%> |
<%= link_to 'Back', users_path %>
我应该意识到它何时报告哈希值。
答案 1 :(得分:0)
你无法渲染展示页面,因为如果你这样做,你会得到一个no方法或nil类。
您的show动作没有名为@user的实例变量。
要让您的节目显示数据,您需要一个用户对象。在你的情况下你没有。
所以在你的show方法中,添加:
@ user.find_by(PARAMS [:ID])
这将找到用户6或7,并允许您拨打@
您可以从浏览器粘贴网址,以便查看您的实际位置吗?