我有以下代码snipplet：
<script>
var textstring =
'Lorem ipsum dolor sit amet, consectetuer adipiscing elit. Aenean commodo ligula eget dolor. Aenean massa.
Cum sociis natoque penatibus et magnis dis parturient montes, nascetur ridiculus mus.';
function insertNewLines(textstr, nos) {
var resulttext = '';
textstr = textstr.replace("\n", "<br />");
while (textstr.length > 0) {
resulttext += textstr.substring(0, nos) + '<br/>';
textstr = textstr.substring(nos);
}
textstring中的文本是2行，即有一个\ r \ n分隔第二行的第一行。 当我调用该函数时，它甚至在我得到替换部件之前就给出了一个错误。 （调试器说因为断行而没有正确关闭块）
有没有办法解决这个问题？我只需要摆脱换行，甚至更好地保留它，但让脚本正确运行。
感谢您的帮助。
TheVagabond
答案 0 :(得分：2)
该代码中存在两个基本语法错误：
除非用反斜杠转义它，否则不能在字符串文字中添加换行符。 （您可以在ES2015模板文字中，但不能使用字符串文字。）如果这样做，则换行符 <bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="packagesToScan">
<array>
<value>my.entity.store.package</value>
</array>
</property>
<property name="persistenceUnitName" value="mainPersistenceUnit" />
<property name="dataSource" ref="dataSource" />
<property name="jpaVendorAdapter" ref="jpaVendorAdapter" />
<property name="jpaDialect" ref="jpaDialect" />
<property name="jpaPropertyMap">
<map>
<entry key="hibernate.hbm2ddl.auto" value="validate" />
<entry key="hibernate.show_sql" value="true" />
<entry key="hibernate.format_sql" value="true" />
<entry key="hibernate.proc.param_null_passing" value="true" />
</map>
</property>
</bean>
。
您错过了函数
\r\n
除此之外，不需要循环; JavaScript的}可以接受带有replace标记的正则表达式（对于“global”），所以：
g
我已使用var textstring =
'Lorem ipsum dolor sit amet, consectetuer adipiscing elit. Aenean commodo ligula eget dolor. Aenean massa.\r\nCum sociis natoque penatibus et magnis dis parturient montes, nascetur ridiculus mus.';
function insertNewLines(textstr, nos) {
return textstr.replace(/\r\n/g, "<br />");
}
console.log(insertNewLines(textstring));替换了文字换行符，然后使用\r\n的单个调用替换了循环。
答案 1 :(得分：-1)
首先确定你的刺痛lilke，
var textstring ='Lorem ipsum dolor sit amet, consectetuer adipiscing elit. Aenean commodo ligula eget dolor. Aenean massa.\
Cum sociis natoque penatibus et magnis dis parturient montes, nascetur ridiculus mus.';
在你的函数中添加一个括号，它应该可以工作。
function insertNewLines(textstr, nos) {
var resulttext = '';
textstr = textstr.replace("\n", "<br />");
while (textstr.length > 0) {
resulttext += textstr.substring(0, nos) + '<br/>';
textstr = textstr.substring(nos);
}
}
答案 2 :(得分：-1)
JavaScript字符串中的换行符应使用反斜杠（public class PlayPauseDrawable extends Drawable {
private static final Property<PlayPauseDrawable, Float> PROGRESS =
new Property<PlayPauseDrawable, Float>(Float.class, "progress") {
@Override
public Float get(PlayPauseDrawable d) {
return d.getProgress();
}
@Override
public void set(PlayPauseDrawable d, Float value) {
d.setProgress(value);
}
};
private final Path mLeftPauseBar = new Path();
private final Path mRightPauseBar = new Path();
private final Paint mPaint = new Paint();
private final RectF mBounds = new RectF(0,0,10,10);
private final float mPauseBarWidth;
private final float mPauseBarHeight;
private final float mPauseBarDistance;
private float mWidth;
private float mHeight;
private float mProgress;
private boolean mIsPlay;
public PlayPauseDrawable(Context context) {
final Resources res = context.getResources();
mPaint.setAntiAlias(true);
mPaint.setStyle(Paint.Style.FILL);
mPaint.setColor(Color.DKGRAY);
mPauseBarWidth = res.getDimensionPixelSize(R.dimen.pause_bar_width);
mPauseBarHeight = res.getDimensionPixelSize(R.dimen.pause_bar_height);
mPauseBarDistance = res.getDimensionPixelSize(R.dimen.pause_bar_distance);
}
@Override
protected void onBoundsChange(Rect bounds) {
super.onBoundsChange(bounds);
mBounds.set(bounds);
mWidth = mBounds.width();
mHeight = mBounds.height();
}
@Override
public void draw(Canvas canvas) {
mLeftPauseBar.rewind();
mRightPauseBar.rewind();
// The current distance between the two pause bars.
final float barDist = lerp(mPauseBarDistance, 0, mProgress);
// The current width of each pause bar.
final float barWidth = lerp(mPauseBarWidth, mPauseBarHeight / 2f, mProgress);
// The current position of the left pause bar's top left coordinate.
final float firstBarTopLeft = lerp(0, barWidth, mProgress);
// The current position of the right pause bar's top right coordinate.
final float secondBarTopRight = lerp(2 * barWidth + barDist, barWidth + barDist, mProgress);
// Draw the left pause bar. The left pause bar transforms into the
// top half of the play button triangle by animating the position of the
// rectangle's top left coordinate and expanding its bottom width.
mLeftPauseBar.moveTo(0, 0);
mLeftPauseBar.lineTo(firstBarTopLeft, -mPauseBarHeight);
mLeftPauseBar.lineTo(barWidth, -mPauseBarHeight);
mLeftPauseBar.lineTo(barWidth, 0);
mLeftPauseBar.close();
// Draw the right pause bar. The right pause bar transforms into the
// bottom half of the play button triangle by animating the position of the
// rectangle's top right coordinate and expanding its bottom width.
mRightPauseBar.moveTo(barWidth + barDist, 0);
mRightPauseBar.lineTo(barWidth + barDist, -mPauseBarHeight);
mRightPauseBar.lineTo(secondBarTopRight, -mPauseBarHeight);
mRightPauseBar.lineTo(2 * barWidth + barDist, 0);
mRightPauseBar.close();
canvas.save();
// Translate the play button a tiny bit to the right so it looks more centered.
canvas.translate(lerp(0, mPauseBarHeight / 8f, mProgress), 0);
// (1) Pause --> Play: rotate 0 to 90 degrees clockwise.
// (2) Play --> Pause: rotate 90 to 180 degrees clockwise.
final float rotationProgress = mIsPlay ? 1 - mProgress : mProgress;
final float startingRotation = mIsPlay ? 90 : 0;
canvas.rotate(lerp(startingRotation, startingRotation + 90, rotationProgress), mWidth / 2f, mHeight / 2f);
// Position the pause/play button in the center of the drawable's bounds.
canvas.translate(mWidth / 2f - ((2 * barWidth + barDist) / 2f), mHeight / 2f + (mPauseBarHeight / 2f));
// Draw the two bars that form the animated pause/play button.
canvas.drawPath(mLeftPauseBar, mPaint);
canvas.drawPath(mRightPauseBar, mPaint);
canvas.restore();
}
public Animator getPausePlayAnimator() {
final Animator anim = ObjectAnimator.ofFloat(this, PROGRESS, mIsPlay ? 1 : 0, mIsPlay ? 0 : 1);
anim.addListener(new AnimatorListenerAdapter() {
@Override
public void onAnimationEnd(Animator animation) {
mIsPlay = !mIsPlay;
}
});
return anim;
}
public boolean isPlay() {
return mIsPlay;
}
private void setProgress(float progress) {
mProgress = progress;
invalidateSelf();
}
private float getProgress() {
return mProgress;
}
@Override
public void setAlpha(int alpha) {
mPaint.setAlpha(alpha);
invalidateSelf();
}
@Override
public void setColorFilter(ColorFilter cf) {
mPaint.setColorFilter(cf);
invalidateSelf();
}
@Override
public int getOpacity() {
return PixelFormat.TRANSLUCENT;
}
/**
* Linear interpolate between a and b with parameter t.
*/
private static float lerp(float a, float b, float t) {
return a + (b - a) * t;
}
）进行转义。
您的变量\也需要更新，如下所示。
textstring答案 3 :(得分：-1)
您必须使用反斜杠转义文字字符串，也没有右括号。下面的代码使用反斜杠进行转义，脚本正在运行。但是输出是您想要的未经检查的。
var textstring =
'Lorem ipsum dolor sit amet, consectetuer adipiscing elit. Aenean commodo ligula eget dolor. Aenean massa.\
Cum sociis natoque penatibus et magnis dis parturient montes, nascetur ridiculus mus.';
insertNewLines(textstring,2);
function insertNewLines(textstr, nos) {
var resulttext = '';
textstr = textstr.replace("\n", "<br />");
while (textstr.length > 0) {
resulttext += textstr.substring(0, nos) + '<br/>';
textstr = textstr.substring(nos);
}
}