来自PHP中的JSON字符串的preg_match

Question

我需要preg_match这个   “supportsUnlock”：true，

代码json

{
  "supportsUnlock" : true,
  "options" : [ "email", "questions" ],
  "account" : {
    "name" : "a@hotmail.com"
  },
  "emailAddress" : "a•••••@hotmail.com",
  "emailDomain" : "hotmail.com",
  "rescueEmail" : false,
  "forgotPasswordFlow" : true
}

Answer 1

首先在$ json varibale中存储json

解码后

。

 $data = json_decode($json);

 print_r($data);

按数组获取值后检查结果。

Answer 2

您可以使用json_decode()函数从json获取值。

示例：

<?php
$json = '{
  "supportsUnlock" : true,
  "options" : [ "email", "questions" ],
  "account" : {
    "name" : "a@hotmail.com"
  },
  "emailAddress" : "a•••••@hotmail.com",
  "emailDomain" : "hotmail.com",
  "rescueEmail" : false,
  "forgotPasswordFlow" : true
}';

$decodeJson = json_decode($json,true);
echo "<pre>";
print_r($decodeJson);
echo $decodeJson['supportsUnlock']; // true

?>

print_r（）的结果：

Array
(
    [supportsUnlock] => 1
    [options] => Array
        (
            [0] => email
            [1] => questions
        )

    [account] => Array
        (
            [name] => a@hotmail.com
        )

    [emailAddress] => a•••••@hotmail.com
    [emailDomain] => hotmail.com
    [rescueEmail] => 
    [forgotPasswordFlow] => 1
)

另请注意，json_decode(string,true)如果您需要在对象中获得结果，则会以数组格式返回结果，而不是删除TRUE的第二个参数。