Question

我正在使用node.js.我有这个函数，它使用promises在执行某些操作之间引入延迟。

function do_consecutive_action() {
    Promise.resolve()
        .then(() => do_X() )
        .then(() => Delay(1000))
        .then(() => do_Y())
        .then(() => Delay(1000))
        .then(() => do_X())
        .then(() => Delay(1000))
        .then(() => do_Y())
    ;
}

我想要做的是让这组动作永远重演。如何在node.js中完成？

//make following actions repeat forever
do_X() 
Delay(1000)
do_Y()
Delay(1000)

编辑：我为使用重复队列来解决问题的答案开始了赏金。

Answer 1

只需使用递归

function do_consecutive_action() {
    Promise.resolve()
        .then(() => do_X() )
        .then(() => Delay(1000))
        .then(() => do_Y())
        .then(() => Delay(1000))
        .then(() => do_consecutive_action())
        // You will also want to include a catch handler if an error happens
        .catch((err) => { ... });
}

Answer 2

function cb(func) {
   try {
       func();
   }
   catch (e) {
      do_consecutive_action();
   }
}

function do_consecutive_action() {
Promise.resolve()
    .then(() => cb(do_X))
    .then(() => Delay(1000))
    .then(() => cb(do_Y))
    .then(() => Delay(1000))
    .then(() => do_consecutive_action())
    // You will also want to include a catch handler if an error happens
    .catch((err) => { ... });

}

在node.js中永远重复这组操作

2 个答案: