Question

我对Javascript承诺的世界相当新，并且在实现以下方面遇到了问题：

var Promise = require('bluebird');
var jenkinsapi = require('jenkins-api');
var asyncJenkinsAPI = Promise.promisifyAll(jenkinsapi);
var jenkins = asyncJenkinsAPI.init("http://<user>:<password>@localhost:8080");

app.get('/api/servers', function(req, resp) {
    SavedJob.find({})
        .then(function(jobs) {
            return Promise.all(jobs.map(function(job){
                // do two calls with each job.name
                // build new data with the result of the two calls
                // return new data to next part of chain
                var job_status = jenkins.job_info(job.name, function(err, jobData) { return jobData; });
                var build_info = jenkins.last_build_info(job.name, function(err, buildData) { return buildData; });
                return {task_name: job_status.name,
                        status: STATUSMAP[job_status.color] || "UNKNOWN",
                        latest_build:
                            {
                                build_date: build_info.timestamp,
                                build_status: build_info.result,
                                build_number: build_info.number,
                                build_url: build_info.url
                            }
                        };
            }));
        })
        .then(function(results){
            console.log(results);
        });
    });

我如何才能最好地在每个Promise.all()的{{1}}内实现两次异步调用，并在结尾处设置一组结果？

Answer 1

在宣传了jenkins之后，您将需要使用新的承诺返回方法：

var job_promise = jenkins.job_infoAsync(job.name);
var build_promise = jenkins.last_build_infoAsync(job.name);

（您可能希望将{suffix: "_async"}作为option to promisifyAll传递给更好的方法名称。）

然后结合这两个承诺（Promise.all / Promise.props / Promise.join）：

return Promise.join(job_promise, build_promise, function(job_status, build_info) {
    return {
        task_name: job_status.name,
        status: STATUSMAP[job_status.color] || "UNKNOWN",
        latest_build: {
            build_date: build_info.timestamp,
            build_status: build_info.result,
            build_number: build_info.number,
            build_url: build_info.url
        }
    };
});

你的其余代码（映射，链接）工作正常。

如何使用Promises实现这种类型的逻辑？

1 个答案: