来自已知键值的php多维数组

时间:2010-10-10 19:23:15

标签: php arrays multidimensional-array

我在这个庞大的扁平单个数组中有一组键我想基本上将该数组扩展为由键组织的多维数组 - 这是一个例子:

'invoice/products/data/item1'
'invoice/products/data/item2'
'invoice/products/data/item2'

=>

'invoice'=>'products'=>array('item1','item2','item3')

我该怎么做 - 上面字符串的长度是可变的......

谢谢!

3 个答案:

答案 0 :(得分:5)

$src = array(
'invoice/products/data/item1',
'invoice/products/data/item2',
'invoice/products/data/item2',
'foo/bar/baz',
'aaa/bbb'
);

function rsplit(&$v, $w)
{
    list($first, $tail) = explode('/', $w, 2);
    if(empty($tail)) 
    {
        $v[] = $first;
        return $v;
    }
    $v[$first] =  rsplit($v[$first], $tail);
    return $v;

}

$result = array_reduce($src, "rsplit");
print_r($result);

输出是:

Array (
    [invoice] => Array
        (
            [products] => Array
                (
                    [data] => Array
                        (
                            [0] => item1
                            [1] => item2
                            [2] => item2
                        )

                )

        )

    [foo] => Array
        (
            [bar] => Array
                (
                    [0] => baz
                )

        )

    [aaa] => Array
        (
            [0] => bbb
        )

)

答案 1 :(得分:2)

沿着这些方向:(虽然没有测试!)立即行动;)

$data = array();
$current = &$data;
foreach($keys as $value) {
  $parts = explode("/", $value);
  $parts_count = count($parts);
  foreach($parts as $i => $part) {
    if(!array_key_exists($part, $current)) {
      if($i == $parts_count - 1) {
        $current[] = $part;
      }
      else {
        $current[$part] = array();
        $current = &$current[$part];
      }
    }
    else {
      $current = &$current[$part];
    }
  }
  $current = &$data;
}

$ keys 是平面阵列。

答案 2 :(得分:0)

虽然从你的问题中不清楚“/”分隔字符串将如何映射到数组,但基本方法可能是这样的:

$result = array();
$k1 = $k2 = '';
ksort($yourData); // This is the key (!)
foreach ($yourData as $k => $v) {
  // Use if / else if / else if to watch for new sub arrays and change
  // $k1, $k2 accordingly
  $result[$k1][$k2] = $v;
}

这种方法使用kso​​rt来确保同一“级别”的键出现在一起,如下所示:

'invoice/products/data1/item1'
'invoice/products/data1/item2'
'invoice/products/data2/item3'
'invoice/products2/data3/item4'
'invoice/products2/data3/item5'

注意ksort如何与您所瞄准的键分组相对应。