Question

我在test1.php中有输入表单，我想检查数据库中的用户输入，如果用户输入在数据库中不存在，则进入test2.php并在test2.php中回显用户输入。否则，重定向回test1.php和echo，不可用。

现在，如果输入存在于sql中，我可以重定向回上一页但是在关闭连接后我无法在test2.php中回显用户输入。

这是test1.php

<!doctype HTML>
<html>
<head>
</head>
<?php
if( isset($_SESSION['ERRMSG_ARR']) && is_array($_SESSION['ERRMSG_ARR']) && count($_SESSION['ERRMSG_ARR']) >0 ) {
    echo '<ul class="err">';
    foreach($_SESSION['ERRMSG_ARR'] as $msg) {
        echo '<li>',$msg,'</li>'; 
    }
    echo '</ul>';
    unset($_SESSION['ERRMSG_ARR']);
}
?>
<form id="loginForm" name="loginForm" method="post" action="test-exec.php">
<table width="300" border="0" align="center" cellpadding="2" cellspacing="0">
<tr>
<th>Email </th>
<td><input name="box" type="text" class="textfield" id="box" /></td>
</tr>
<td><input type="submit" name="Submit" value="Check" /></td>
</tr>
</table>
</form>

这是test-exec.php

<?php
session_start();

require_once('db/config.php');

$errmsg_arr = array();

$errflag = false;

    $con = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_DATABASE);
if(!$con) {
    die('Failed to connect to server: ' . mysqli_connect_error());
}

$db = mysqli_select_db($con, DB_DATABASE);
if(!$db) {
    die("Unable to select database");
}

$box = mysqli_real_escape_string($con, $_POST['box']);

if($box != '') {
    $qry = "SELECT * FROM members WHERE box='$box'";
    $result = mysqli_query($con,$qry);
    if($result) {
        if(mysqli_num_rows($result) > 0) {
            $errmsg_arr[] = 'Box already in use';
            $errflag = true;
        }
        @mysql_free_result($result);
    }
    else {
        die("Query failed");
    }
}

if($errflag) {
    $_SESSION['ERRMSG_ARR'] = $errmsg_arr;
    session_write_close();
    header("location: test1.php");
    exit();
}else {
    header("location: test2.php");
    exit();

mysqli_close($con);

}
?>

这里是test2.php

<!doctype HTML>
<html>
<head>
</head>

<form id="loginForm" name="loginForm" method="post" action="register.php">
<table width="300" border="0" align="center" cellpadding="2" cellspacing="0">
<tr>
<th>Email </th>
<td><input name="box" type="text" class="textfield" id="box" value="<?php echo $_POST['box']; ?>" /></td>
</tr>
<td><input type="submit" name="submit" value="Submit" /></td>
</tr>
</table>
</form>

Answer 1

if($errflag) {
    $_SESSION['ERRMSG_ARR'] = $errmsg_arr;
    session_write_close();
    header("location: test1.php");
    exit();
}else {
    $_SESSION['SESS_box'] = $box;
    session_write_close();
    header("location: test2.php");
    exit();

    mysqli_close($con);
}
?>


then in the html use this:
<?php echo $_SESSION["SESS_box"]; ?> 
to echo the input.

如何在db中检查用户输入并关闭连接，然后在下一页上回显输入

1 个答案: