其他声明不能在javascript中工作（只返回if和if else）

Question

我在做一个简单的石头剪刀游戏的JavaScript项目，我似乎无法弄清楚为什么我的代码只返回“玩家获胜”，即使玩家应该输掉。这是代码：

var userChoice = prompt("Do you choose rock, paper or scissors?");
console.log("Player: " + userChoice)

var computerChoice = Math.random();
console.log(computerChoice)

if (computerChoice < 0.34) {
  computerChoice = "rock"
} else if (computerChoice > 0.67) {
  computerChoice = "paper"
} else {
  computerChoice = "scissors"
}
console.log("Computer: " + computerChoice);

var compare = function(userChoice, computerChoice) {
  var x = userChoice
  var y = computerChoice
  if (x === y) {
    return "The result is a tie!"
  }
  if (x === "rock", y === "scissors") {
    return "player wins"
  } else if (x === "scissors", y === "paper") {
    return "player wins"
  } else if (x === "paper", y === "rock") {
    return "player wins"
  } else {
    return "You lose"
  }
}

compare(userChoice, computerChoice)

另外在旁注中，为什么stackoverflow上的控制台在codeacademy上的控制台没有显示返回时。

Answer 1

您应该使用运算符&&而不是,。

var compare = function(userChoice, computerChoice) {
  var x = userChoice;
  var y = computerChoice;

  if (x === y) {
    return "The result is a tie!";
  }
  if (x === "rock" && y === "scissors") {
    return "player wins";
  } else if (x === "scissors" && y === "paper") {
    return "player wins";
  } else if (x === "paper" && y === "rock") {
    return "player wins";
  } else {
    return "You lose";
  }
}

Answer 2

我猜你丢了东西，也许你应该改变：

if (x === "rock", y === "scissors") {

到

if (x === "rock" && y === "scissors") {

其他条件陈述应如上所述。