PHP：仅显示在“今天”，而不是“昨天”

Question

$today = time() - (3600*24);
$Yday = time() - (3600*48);

$getMsgsToday = mysql_query("SELECT * FROM users_msgs WHERE uID = '$USER' AND date > $today");
$countToday = mysql_num_rows($getMsgsToday);

$getMsgsYday = mysql_query("SELECT * FROM users_msgs WHERE uID = '$USER' AND date > $Yday");
$countYday = mysql_num_rows($getMsgsYday);

这是我最近24小时48小时（昨天）显示消息的代码。

我有两个问题（昨天和今天）。

现在如果你在24小时内有东西，它也会在昨天的时候显示（）。

我只希望显示昨天的消息，我的意思是今天24小时之前的24小时。

我怎么能这样做，所以我不会得到这些副本？

Answer 1

使用BETWEEN … AND …仅选择48小时到24小时之前的那些：

"SELECT * FROM users_msgs WHERE uID = '$USER' AND date BETWEEN $Yday AND $today"

Answer 2

$getMsgsYday = mysql_query("SELECT * FROM users_msgs WHERE uID = '$USER' AND date BETWEEN $Yday and $today");