Question

我有一个带for循环的函数。它遍历一个列表并将每个值打印到控制台我想在函数的末尾添加一个return语句，所以当我调用函数时，我可以返回所有的值。我想我需要将其作为列表返回。

我的功能是：

def extract_header_from_summary_from_report_htmltestrunner():
    filename = (r"C:\temp\selenium_report\ClearCore501_Automated_GUI_TestReport.html")    html_report_part = open(filename,'r')
    soup = BeautifulSoup(html_report_part, "html.parser")
    table = soup.select_one("#result_table")
    headers = [td.text for td in table.select_one("#header_row").find_all("td")[1:-1]]
    print(" ".join(headers))
    for row in table.select("tr.passClass"):
        print(" ".join([td.text for td in row.find_all("td")[1:-1]]))

如何将返回结束并从for循环中返回每个值？

for循环打印出以下内容：

Count Pass Fail Error
75 75 0 0

谢谢Riaz

Answer 1

什么阻止你创建一个空列表并附加到它？

def extract_header_from_summary_from_report_htmltestrunner():
    filename = (r"C:\temp\selenium_report\ClearCore501_Automated_GUI_TestReport.html")    html_report_part = open(filename,'r')
    soup = BeautifulSoup(html_report_part, "html.parser")
    table = soup.select_one("#result_table")

    #Create list here...
    results = []

    headers = [td.text for td in table.select_one("#header_row").find_all("td")[1:-1]]
    print(" ".join(headers))

    #Don't forget to append header (if you want)
    results.append(headers)

    for row in table.select("tr.passClass"):
        #Store row string in variable and append before printing
        row_str = " ".join([td.text for td in row.find_all("td")[1:-1]]))
        results.append(row_str)
        print(row_str)

    return results

Answer 2

您可以产生每个字符串：

list(extract_header_from_summary_from_report_htmltestrunner())

然后调用for row in extract_header_from_summary_from_report_htmltestrunner(): # use each row或迭代生成器函数：

=(SUMIF(A5:A230,K5:K15,C5:C230))

BeautifulSoup Python如何将my循环中的所有值作为我的函数中的列表返回

2 个答案: