年龄列不在表passenger
中。显示老年乘客的姓名和出生日期(年龄> = 60)并且我已经使用了
查询:
select
passname,
(extract(year from current_date) - extract(year from passdob)) >60
from
passenger
答案 0 :(得分:2)
尝试使用:
SELECT passname, passdob
FROM passenger
WHERE (EXTRACT(YEAR FROM current_date)-EXTRACT(YEAR FROM passdob)) >60
答案 1 :(得分:1)
尝试使用
char choice;
cout <<"1: Exit\n2: Print Mark\n3: Print Name"<<endl;
cin >> choice;
while (choice != '1' && choice != '2' && choice != '3')
{
cout << "Invalid Choice <<endl;
cout <<"1: Exit\n2: Print Mark\n3: Print Name"<<endl;
cin >> choice;
}