从Epoch开始,将Pandas Timestamp转换为nano的最有效方法是什么?
import pandas as pd
ns = 1470924597871000000
timestamp = pd.to_datetime(ns, unit="ns")
然后如何
timestamp => 1470924597871000000 ns???
答案 0 :(得分:6)
对我来说,它适用于参数unit
,但令人惊讶的是没有参数:
import pandas as pd
ns = 1470924597871000000
timestamp1 = pd.to_datetime(ns)
print (timestamp1)
2016-08-11 14:09:57.871000
timestamp = pd.to_datetime(ns, unit='ns')
print (timestamp)
2016-08-11 14:09:57.871000
如果需要从Timestamp转换为epoch:
print (timestamp.value)
1470924597871000000
答案 1 :(得分:1)
传递unit='ns'
以指定单位类型:
In [46]:
ns = 1470924597871000000
timestamp = pd.to_datetime(ns, unit='ns')
timestamp
Out[46]:
Timestamp('2016-08-11 14:09:57.871000')
但是,除非你追求别的东西,否则这似乎没有通过这个似乎很好吗?
您可以使用timestamp()
获取时间戳值:
In [50]:
timestamp.timestamp()
Out[50]:
1470920997.871
答案 2 :(得分:1)
您可以通过其值访问它:
import pandas as pd
ns = 1470924597871000000
timestamp = pd.to_datetime(ns)
timestamp.value
Out: 1470924597871000000