PHP无法从URL获取文本(file_get_content,CURL不起作用)

时间:2016-08-11 08:55:28

标签: php http url curl file-get-contents

我正在尝试从以下网址获取文字。 http://stp.stheadline.com/data/indexNewsMarquee.json

我尝试了几种方法,但没有一种方法可行。我现在非常绝望,请提前帮助我,谢谢。

P.S。我已经在我的ini.php中启用了 allow_url_fopen 。 附:我正在使用XAMPP v3.3.2和PHP v5.6.23

以下是我尝试过的代码(并且失败了)

CURL

$ch = curl_init();
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL, $url);
$result = curl_exec($ch);
curl_close($ch);
echo $result;

结果:空字符串

的file_get_contents

echo file_get_contents($url, true);

结果:无法打开流:HTTP请求失败!

的ReadFile

echo readfile($url)

结果:输出地址本身

5 个答案:

答案 0 :(得分:2)

他们要求在请求中出现useragent,所以请尝试:

$url='http://stp.stheadline.com/data/indexNewsMarquee.json';
$ch = curl_init();
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_USERAGENT, 'banana');
curl_setopt($ch, CURLOPT_URL, $url);
$result = curl_exec($ch);
curl_close($ch);
echo $result;

答案 1 :(得分:2)

您好,您必须在curl请求中传递标题,因此服务器可以将其视为浏览器请求。

 $url="http://stp.stheadline.com/data/indexNewsMarquee.json";

 $requestHeaders = array(
    "Accept:application/json, text/javascript, */*; q=0.01",
    "Accept-Language:en-US,en;q=0.8",
    "Connection:keep-alive",
    "Host:stp.stheadline.com",
    "Origin:http://stp.stheadline.com",
    "Referer:http://stp.stheadline.com/data/indexNewsMarquee.json",
    "User-Agent:Mozilla/5.0 (Windows NT 6.1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/49.0.2623.87 Safari/537.36"
 );

 $ch = curl_init();
 curl_setopt($ch, CURLOPT_URL, $url);
 curl_setopt($ch, CURLOPT_HTTPHEADER, $requestHeaders);
 curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
 $output = curl_exec($ch);
 curl_close($ch);
 echo $output;

答案 2 :(得分:0)

使用就像这样:

 $curl_handle=curl_init();
 curl_setopt($curl_handle,CURLOPT_URL,'Your URL');
 curl_setopt($curl_handle, CURLOPT_CONNECTTIMEOUT, 2);
 curl_setopt($curl_handle, CURLOPT_RETURNTRANSFER, 1);
 curl_setopt($curl_handle, CURLOPT_USERAGENT, 'Your application name');
$query = curl_exec($curl_handle);
curl_close($curl_handle);
print_r($query);

我从您的网址检查了此代码。

答案 3 :(得分:0)

试一试。

$ch = curl_init();
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL, 'http://stp.stheadline.com/data/indexNewsMarquee.json');
$result = curl_exec($ch);
curl_close($ch);

echo($result); // Json data

/*$obj = json_decode($result); // To get result in array
print_r($obj);*/

或者

$url = 'http://stp.stheadline.com/data/indexNewsMarquee.json';
$ch = curl_init();
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL, $url);
$result = curl_exec($ch);
curl_close($ch);

echo($result); // Json data

这对我有用:)

答案 4 :(得分:0)

凯文,

请尝试以下代码。

header('Content-Type: text/html; charset=utf-8');

$url='http://stp.stheadline.com/data/indexNewsMarquee.json';

$ch = curl_init();
curl_setopt($ch, CURLOPT_HTTPHEADER, array('text/html; charset=utf-8'));
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_ENCODING, "");
curl_setopt($ch, CURLOPT_URL, $url);
$result = curl_exec($ch);
curl_close($ch);
$final_result = json_decode($result);

echo "<pre>";
print_r($final_result);

我在您的代码中添加了header('Content-Type: text/html; charset=utf-8');curl_setopt($ch, CURLOPT_ENCODING, "");,它会很好用,也会显示正确的字符。