Question

我必须按升序对字典值进行排序。然后我必须从字典中排除零元素。我发现了很多按键或值排序字典的例子而不是值本身。对此有何帮助？

输入：

1467606570.0,192.168.123.241,0.0
1467606817.0,192.168.123.241,247.0
1467607136.0,192.168.123.241,319.0
1467607244.0,192.168.123.241,108.0
1467607642.0,192.168.123.241,398.0
1467608334.0,192.168.123.241,692.0
1467606628.0,192.168.123.240,0.0
1467606876.0,192.168.123.240,248.0
1467607385.0,192.168.123.240,509.0
1467606679.0,192.168.123.246,0.0
1467607084.0,192.168.123.246,405.0
1467607713.0,192.168.123.246,629.0
1467608102.0,192.168.123.246,389.0
1467607524.0,192.168.123.242,0.0
1467608257.0,192.168.123.242,733.0
1467608607.0,192.168.123.242,350.0
1467608669.0,192.168.123.245,0.0
1467608813.0,192.168.123.245,144.0

代码：

    mydict = {}
    #sorted_dict = {}
    reader = csv.reader(open("/tmp/log/qpm.csv", "rb"))
    for i, rows in enumerate(reader):
       if i == 0: continue
       k = rows[1]
       v = rows[2]

       if not k in mydict:
       mydict[k] = [v]
       else:
       mydict[k].append(v)

    #for key, value in mydict.iteritems():
    for key, value in sorted (mydict.iteritems(), key=operator.itemgetter(1),reverse=True):
        print key, value

输出：

192.168.123.241 ['247.0', '319.0', '108.0', '398.0', '692.0']
192.168.123.242 ['0.0', '733.0', '350.0']
192.168.123.246 ['0.0', '405.0', '629.0', '389.0']
192.168.123.240 ['0.0', '248.0', '509.0']
192.168.123.245 ['0.0', '144.0']

必需输出：

192.168.123.241 ['108.0', '319.0', '398.0', '692.0']
192.168.123.242 ['0.0', '350.0', '733.0']
192.168.123.246 ['0.0', '389.0', '405.0', '629.0']
192.168.123.240 ['0.0', '248.0', '509.0']
192.168.123.245 ['0.0', '144.0']

如何按升序排序值？

Answer 1

根据示例输出，我怀疑您想要为每个键排序值吗？如果是这样，您可以通过将print语句更改为：

来完成此操作

print key, sorted(value)

请注意，values列表中的条目是字符串，因此将按字典顺序排序，我怀疑这不是您想要的。要排序为浮点数，您可以指定自定义比较器：

print key, sorted(value, key=lambda x: float(x))

或者，您可以在最初读取数据时将值存储为浮点数：

 if not k in mydict:
     mydict[k] = [float(v)]
 else:
     mydict[k].append(float(v))

如何按升序对字典的多个值进行排序？

1 个答案: