我想像父母一样下拉，孩子意味着使用bootstrap CSS进行多级任务。 我尝试了下面的一个，但我得到了所有课程名称的孩子。我想下拉像
Linux的 --Linux Basics
CSS --CSS基础知识
以下是我的代码：
Desktop.browse(...)下面是我的数组值：
Desktop.browse(...)答案 0 :(得分：2)
你正在创建一个很难实现的非常复杂的数组;）
试试这个数组：
$arrCourses = $this->objWsCoursesModel->getMainMenuCourses();
$outResults = array();
for($i=0; $i<count($arrCourses); $i++){
$courseName = isset($arrCourses[$i]['course_name']) ? $arrCourses[$i]['course_name'] : '';
$outResults['mainCourse'][$courseName][] = isset($arrCourses[$i]['course_slug_name']) ? $arrCourses[$i]['course_slug_name'] : '';;
}
试试这段代码。这是一种粗略的代码。我不确定任何语法错误，但我认为它会像这样工作：
<ul>
<?php foreach($outContentArrResults AS $courseName=> $valArrMenu){ ?>
<li class="menu-item-has-children">
<a href="#"><?php echo $courseName ?></a>
<ul class="sub-menu" style="border-right: 2px solid #012340;border-left: 2px solid #012340;">
<?php for($valArrMenu as $row){?>
<li>
<a href="<?php echo $config['LIVE_URL'];?>courses/<?php isset($valArrMenu['slug'][$i]) ? $valArrMenu['slug'][$i]:'';?>"><?php echo isset($valArrMenu[$i]) ? $valArrMenu[$i]:'';?></a>
</li>
<?php } ?>
</ul>
</li>
<?php } ?>
</ul>
答案 1 :(得分：1)
您可以尝试这样，它以Array格式返回值。我将此函数用于Item category Tree，
function categoryDropDown($categoryArray, $parentId, $level, $options)
{
$level++;
foreach ($categoryArray as $array)
{
if($array['parentId'] == $parentId)
{
$opt = $array['name'] ;
$categoryLevel = $level -1;
$options[$array['id']] = array("id"=> $array['id'], "categoryName"=>"$opt","level" => "$categoryLevel", "status" => $array['status']);
$newParent = $array['id'];
$options = categoryDropDown($categoryArray, $newParent, $level , $options);
}
}
return $options;
}
---- ----输出
$options= categoryDropDown(); //now it will converted into an Array.
所以你可以打印这样的选项
<?php
foreach($options as $value)
{
?>
<option value="<?php echo $value['id']; ?>"> <?echo $value['categoryName']; ?> </option>
//Which is similar to <option value="option name/id">Option 1</option>
<?php
}
?>
数组输出如下（此处索引是我的数据库中的主键）
Array
(
[1] => Array
(
[id] => 1
[categoryName] => Electronics
[level] => 0
[status] => d
)
[3] => Array
(
[id] => 3
[categoryName] => Laptops
[level] => 1
[status] => a
)
[6] => Array
(
[id] => 6
[categoryName] => Laptop Accessories
[level] => 2
[status] => a
)
[2] => Array
(
[id] => 2
[categoryName] => Mobile
[level] => 1
[status] => a
)
[5] => Array
(
[id] => 5
[categoryName] => Mobile Accessories
[level] => 2
[status] => d
)
[4] => Array
(
[id] => 4
[categoryName] => Tablet
[level] => 1
[status] => a
)
[12] => Array
(
[id] => 12
[categoryName] => Fashion
[level] => 0
[status] => a
)
[13] => Array
(
[id] => 13
[categoryName] => Men
[level] => 1
[status] => a
)
[15] => Array
(
[id] => 15
[categoryName] => Jeans
[level] => 2
[status] => a
)
[14] => Array
(
[id] => 14
[categoryName] => Women
[level] => 1
[status] => a
)
[16] => Array
(
[id] => 16
[categoryName] => Jeans
[level] => 2
[status] => a
)
[11] => Array
(
[id] => 11
[categoryName] => Main Category 2
[level] => 0
[status] => a
)
[33] => Array
(
[id] => 33
[categoryName] => temp
[level] => 0
[status] => a
)
)
答案 2 :(得分：0)
是的，munjal的解决方案是正确的。而且你正在制作非常复杂的数组结构。 如果你使用jquery和json解析比简单， 在页面上加载调用js函数，您可以在其中为菜单树创建json数组。 从db你可以轻松管理。
答案 3 :(得分：0)
所以这是我对问题的编辑，不确定我是否正确解释了问题：
$config['LIVE_URL'] = 'https://example.com/'
$arr_courses = $this->objWsCoursesModel->getMainMenuCourses();
$menu_data = [];
for ($i = 0; $i < count($arr_courses); $i++)
{
$course_name = isset($arr_courses[$i]['course_name']) ? $arr_courses[$i]['course_name'] : '';
$menu_data['mainCourse'][$course_name]['title'][$i] = $course_name;
$menu_data['mainCourse'][$course_name]['slug'][$i] = isset($arr_courses[$i]['course_slug_name']) ? $arr_courses[$i]['course_slug_name'] : '';
}
// $menu_data should look something like this
$menu_data = [
'linux' => [
'title' => [
'linux Basics',
'first steps',
'last',
'sdd',
'linux sub',
'test sub sub linux',
],
'slug' => [
'linux-basics',
'first-steps',
'last',
'sdd',
'linux-sub',
'test-sub-sub-linux',
],
],
'css' => [
'title' => [
'css',
'css Basics',
'css Introduction',
],
'slug' => [
'css',
'css-basics',
'css-introduction',
],
]
];
?>
<ul class="sub-menu">
<?php foreach($menu_data as $course_name => $data): ?>
<li class="menu-item-has-children">
<a href="#"><?php echo $course_name; ?></a>
<ul class="sub-menu">
<?php for ($i = 0; $i < count($data['slug']); $i++): ?>
<li>
<a href="<?php echo $config['LIVE_URL'];?>courses/<?php echo isset($data['slug'][$i]) ? $data['slug'][$i]:'';?>"><?php echo isset($data['title'][$i]) ? $data['title'][$i]:'';?></a>
</li>
<?php endfor; ?>
</ul>
</li>
<?php endforeach; ?>
</ul>
哪个输出：
linux (href="#")
linux Basics (href=https://example.com/courses/linux-basics)
first steps (...)
last
sdd
linux sub
test sub sub linux
css (href ="#")
css (href=https://example.com/courses/css)
css Basics (...)
css Introduction
从这里你可以添加css来正确设置样式，这不应该是一个太大的问题。