我对jquery很新。我有以下代码。在这里,我想在Fill 3中单击添加按钮获取表中的新行。我成功添加该行,但是当我获得新的div时,我想在填充3中单击添加按钮时在表中获取新行。添加到错误的div。
有人可以告诉我,我在这里做了什么错误吗?
var id = 0; //global id to create unique id
$(document).ready(function() {
//attach click event to element/button with id add and remove
$("#add,#remove").on('click', function() {
var currentElemID = $(this).attr('id'); //get the element clicked
if (currentElemID == "add") { //if it is add elem
var cloneParent = $("#dataTes").clone(); //clone the dataTes element
id=$("div[id^=dataTes]").length + 1;//get the count of dataTes element
//it will be always more than last count each time
cloneParent.find('[id]').each(function() {
//loop through each element which has id attribute in cloned set and replace them
//with incremented value
var $el = $(this); //get the element
$el.attr('id', $el.attr('id') + id);
//ids would now be add1,add2 etc.,
});
cloneParent.attr('id', cloneParent.attr('id') + id);//replace cloneParent id
cloneParent.appendTo('#result');//append the element to fieldset
$("#remove").show();//show remove button only if there is more than one dataTes element
} else {
$("div[id^=dataTes]:last").remove();
//just remove the last dataTes
//[id^=dataTes]:last annotates remove last div whose id begins with dataTes
//remember we have id like dataTes1,dataTes2 etc
if($("div[id^=dataTes]").length==1){
//check if only one element is present
$("#remove").hide();//if yes hide the remove button
}
}
});
});
function addRow(tableID) {
var table = document.getElementById(tableID);
var rowCount = table.rows.length;
var row = table.insertRow(rowCount);
var colCount = table.rows[0].cells.length;
for (var i = 0; i < colCount; i++) {
var newcell = row.insertCell(i);
newcell.innerHTML = table.rows[0].cells[i].innerHTML;
}
}
function deleteRow(tableID) {
var table = document.getElementById(tableID);
var rowCount = table.rows.length;
if (rowCount > 1) {
table.deleteRow(rowCount - 1);
}
else {
alert("Tidak dapat menghapus semua baris!");
}
}
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<fieldset id="result">
<legend>Test</legend>
<input type="submit" class="button" id="add" value="+" title="#">
<input type="submit" class="button" id="remove" value="-" style="display:none;" title="#">
<!--hide the remove button with display:none initially-->
<div id="dataTes">
<table align="center" cellpadding="3" cellspacing="0" style="border-collapse:collapse;margin-top:10px;" width="97%">
<tr>
<td width="100px">Test</td>
<td width="2px">:</td>
<td>
<input type="text" name="usrname">
</td>
</tr>
<table align="center" cellpadding="3" cellspacing="0" style="border-collapse:collapse;margin-top:5px;margin-left:40px;" width="97%">
<tr>
<td width="2px"></td>
<td width="100px">Fill 1</td>
<td width="2px">:</td>
<td>
<input type="text" name="usrname">
</td>
</tr>
<tr>
<td width="2px"></td>
<td width="100px">Fill 2</td>
<td width="2px">:</td>
<td>
<input type="text" name="usrname">
</td>
</tr>
<table id="dataIP" align="center" cellpadding="3" cellspacing="0" style="border-collapse:collapse;margin-left:40px;" width="97%">
<tr>
<td width="2px"></td>
<td width="100px">Fill 3</td>
<td width="2px">:</td>
<td width="2px">
<input type="text" name="usrname">
</td>
<td>
<input type="submit" class="button" value="+" onClick="addRow('dataIP')" title = "#">
<input type="submit" class="button" value="-" onClick="deleteRow('dataIP')" title = "#">
</td>
</tr>
</table>
</table>
</table>
</div>
</fieldset>
&#13;
提前致谢!
答案 0 :(得分:0)
<table id="dataIP" align="center" cellpadding="3" cellspacing="0" style="border-collapse:collapse;margin-left:40px;" width="97%">
<tr>
<td width="2px"></td>
<td width="100px">Fill 3</td>
<td width="2px">:</td>
<td width="2px">
<input type="text" name="usrname">
</td>
<td>
<input type="submit" class="button" value="+" onClick="addRow('dataIP')" title = "#">
<input type="submit" class="button" value="-" onClick="deleteRow('dataIP')" title = "#">
</td>
</tr>
</table>`
所以我们在这里做的是我们将更改addRow(this)而不是addRow(&#39; dataIp&#39;)因为我们知道&#34;这个&#34;关键字在传递元素的ID方面具有高优先级。&#34; this&#34;关键字有一般用途vs将id传递给函数..只需尝试将所有参数更改为&#34; this&#34;。
答案 1 :(得分:0)
function addRow(tableID) {
var par = tableID.parentNode.parentNode.parentNode.id;
var table = document.getElementById(par);
var rowCount = table.rows.length;
var row = table.insertRow(rowCount);
var colCount = table.rows[0].cells.length;
for (var i = 0; i < colCount; i++) {
var newcell = row.insertCell(i);
newcell.innerHTML = table.rows[0].cells[i].innerHTML;
}
当我在输入中更改add和delete函数的参数时,这就是我所做的事情我得到了param父节点元素,用于父元素中特定元素的目的...
}
答案 2 :(得分:0)
顺便说一句..你必须将你的第三个索引表改为tbody。获取父节点的结果将是一个tbody。因为将表放在表中是冗余窗口,所以将其读作tbody 我们必须遵守规则
<table> <tbody> </tbody> <tfoot> </tfoot> </table>