摘要
尝试对INSendPaymentIntent
进行编码,但在区分具有相似名字的联系人时遇到问题。 Siri似乎在INPersonResolutionResult.disambiguation(with: matchedContacts)
守则背后的想法
我选择使用联系人的给定名称来搜索联系人,因为如果用户仅指定名字,则使用INPerson
显示名称将返回与查询匹配的第一个联系人。 (即'Pay Kevin $ 50'将自动选择Kevin Bacon而不是Kevin Spacey)。
不幸的是,使用给定的名称将Siri发送到循环中,要求用户反复指定联系人...
问题
有没有办法使用联系人的名字搜索联系人而不将Siri发送到循环中?
代码
func resolvePayee(forSendPayment intent: INSendPaymentIntent, with completion: (INPersonResolutionResult) -> Void) {
if let payee = intent.payee {
var resolutionResult: INPersonResolutionResult?
var matchedContacts: [INPerson] = []
let predicate = CNContact.predicateForContacts(matchingName: (payee.nameComponents?.givenName)!)
do {
let searchContactsResult = try CNContactStore().unifiedContacts(matching: predicate, keysToFetch:[CNContactGivenNameKey, CNContactFamilyNameKey, CNContactMiddleNameKey, CNContactPhoneNumbersKey, CNContactImageDataKey, CNContactIdentifierKey])
for contact in searchContactsResult {
matchedContacts.append(createContact((contact.phoneNumbers.first?.value.stringValue)!, contact: contact))
}
} catch {
completion(INPersonResolutionResult.unsupported())
}
switch matchedContacts.count {
case 2 ... Int.max:
resolutionResult = INPersonResolutionResult.disambiguation(with: matchedContacts)
case 1:
let recipientMatched = matchedContacts[0]
print("Matched a recipient: \(recipientMatched.displayName)")
resolutionResult = INPersonResolutionResult.success(with: recipientMatched)
case 0:
print("This is unsupported")
resolutionResult = INPersonResolutionResult.unsupported()
default:
break
}
completion(resolutionResult!)
} else {
completion(INPersonResolutionResult.needsValue())
}
}
答案 0 :(得分:1)
Siri会在您退回时确认该人的姓名:
completion(INPersonResolutionResult.needsValue())
或者这个:
completion(INPersonResolutionResult.disambiguation(with: matchedContacts))
在这种情况下,我认为它更有可能进入循环,因为你不断返回第二个结果(INPersonResolutionResult.disambiguation
)。这意味着您在此行中的查询将返回2人或更多人:
let searchContactsResult = try CNContactStore().unifiedContacts(matching: predicate, keysToFetch:[CNContactGivenNameKey, CNContactFamilyNameKey, CNContactMiddleNameKey, CNContactPhoneNumbersKey, CNContactImageDataKey, CNContactIdentifierKey])
我建议你调试那条线,看看你是否给过Siri这个值:
INPersonResolutionResult.success