Question

我正在使用RestSharp来发布以下内容：

POST API/storage
Content-Type: application/xml
<StorageDocument xmlns="http://xml.somename.com/schema/somename">
  <type>LOCAL</type>
  <method>
    <uri>file:///path/to/files/</uri>
    <read>true</read>
    <write>true</write>
    <browse>true</browse>
    <type>NONE</type>
 </method>
 <autoDetect>true</autoDetect>
</StorageDocument>

我的代码：

private void button2_Click(object sender, EventArgs e)
    {
        var client = new RestClient();

        client.BaseUrl = new Uri(baseUrlString);
        client.Authenticator = new HttpBasicAuthenticator("admin", "admin");

        var request = new RestRequest("API/storage", Method.POST);

        request.AddParameter ("Content-Type", "application/xml");
        request.RequestFormat = DataFormat.Xml;

        string xml =
            "<StorageDocument xmlns=\"http://xml.somename.com/schema/somename\">" + Environment.NewLine +
            "<type>LOCAL</type>" + Environment.NewLine +
            "<method>" + Environment.NewLine +
              "<uri>file:///path/to/files/</uri>" + Environment.NewLine +
              "<read>true</read>" + Environment.NewLine +
              "<write>true</write>" + Environment.NewLine +
              "<browse>true</browse>" + Environment.NewLine +
              "<type>NONE</type>" + Environment.NewLine +
            "</method>" + Environment.NewLine +
            "<autoDetect>true</autoDetect>" + Environment.NewLine +
            "</StorageDocument>";


        request.AddBody(xml);

        IRestResponse response = client.Execute(request);

        MessageBox.Show(Convert.ToString(response.Content));
    }

当我发布时，我得到“HTTP 415不支持的媒体类型”。我尝试了很多东西，但无法弄清问题在哪里。我相信它是使用xml或请求的主体但无法找到解决方案。

有什么想法吗？提前致谢

Answer 1

对于我这种情况的人来说，这个代码很有用

private void button2_Click(object sender, EventArgs e)
    {
        var client = new RestClient();

        client.BaseUrl = new Uri(baseUrlString);
        client.Authenticator = new HttpBasicAuthenticator("admin", "admin");


        var request = new RestRequest("API/storage", Method.POST);


        string rawXml = "<StorageDocument xmlns=\"http://xml.somename.com/schema/somename\"><type>LOCAL</type><method><uri>file://home/Testuser/storage/</uri><read>true</read><write>true</write><browse>true</browse><type>NONE</type></method><autoDetect>true</autoDetect></StorageDocument>";

        request.AddParameter("application/xml", rawXml, ParameterType.RequestBody);

        IRestResponse response = client.Execute(request);

        MessageBox.Show(Convert.ToString(response.Content));
    }

关键是使用AddParameter而不是AddBody，这里提到 RestSharp PUT XML, RestSharp is sending it as GET? 作者：Richard Friend

Answer 2

这可能对某人有帮助...这对我有用

            var postUrl = "https://your-api.com/resource/path";
        string rawXml = "<note><to>Tove</to><from>Jani</from><heading>Reminder</heading><body>Don't forget me this weekend!</body></note>";

        IRestClient client = new RestClient();
        IRestRequest request = new RestRequest
        {
            Resource = postUrl
        };

        request.AddHeader("Content-Type", "text/xml");
        request.AddHeader("Accept", "text/xml");
        request.AddParameter("text/xml", rawXml, ParameterType.RequestBody);

        var response = client.Post<Note>(request);

        Assert.IsNotNull(response.Data);

使用RestSharp进行xml POST

2 个答案: